Which line is perpendicular?

Mathematics

1 answer:

Serggg [28]3 years ago

8 0

D. You can find a perpendicular line by finding the inverse equations (-(1/)2 x+3

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Find the area of each parallelogram plz help

xxTIMURxx [149]

Answer: The area of the parallelogram is:
_______________________________________________________
$\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
A = base * height = b * h ;

From the figure (from the actual "question"):
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b = 50.5 in.

h = 23.25 in.
____________________________________________________________
Method 1) A = b * h =

= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 ⅛ .
____________________________________________________________
Method 2) A = b * h =

= (50 ½ in) * (23 ¼ in) =

= ( $\frac{101}{2}$ in) * ( $\frac{93}{4}$ in) ;
___________________________________________________________
Note: "50 ½ " = [(50*2) + 1 ] / 2 = $\frac{101}{2}$ ;

Note: "23 ¼ " = [(23*4) + 1 ] / 4 = $\frac{93}{4}$ ;
____________________________________________________________
→ A = ( $\frac{101}{2}$ in) * ( $\frac{93}{4}$ in) ;

→ A = $\frac{(101*93)}{(2*4)}$ in² = $\frac{9393}{8}$ in² ;

→ A = (9393/8) in² =

→ A = $\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________

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The temperature at 12 noon was 10 degree celsius. If it decreases at the rate of 2 degree celsius per hour until midnight, at wh

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If both diagonals of a quadrilateral bisect each other when is the quadrilateral a parallelogram?

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It is more than just a quadrilateral. In fact it is going to be hard to pick.

These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.

The converse is "If you have a parallelagram, the diagonals bisect each other."

You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.

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Find the area please :)

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