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kap26 [50]
4 years ago
10

A circular swimming pool has a radius of 28 feet there’s a path all the way around the pool dad 4 feet wide inference is going t

o be built around outside edge of the pool by about how many feet of fencing are needed to go around the pool path
Mathematics
1 answer:
Mumz [18]4 years ago
8 0

Answer:

201.06 (2 decimal places)

Step-by-step explanation:

new radius 28 + 4 = 32

diameter = 64

circumference of the fence

= pi x d

= pi x 64

= 201.0619

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Which of the follwing is true 3 3/9+7 6/11=10 87/99 2 3/8+6 4/5=8 12/40 ,3 3/7+4 2/3=7 2/21 4 5/6+5 5/7=9 10/13
garri49 [273]

Answer: 3 3/9+7 6/11 = 10 87/99

Step-by-step explanation:

a. 3 3/9+7 6/11 = 10 87/99

First and foremost, we need to know the lowest common multiple of 9 and 11 which is 99.

Therefore, 3 3/9 + 7 6/11 would be:

= 3 33/99 + 7 54/99

= 10 87/99

This is correct

b. 2 3/8 + 6 4/5 = 8 12/40

First and foremost, we need to know the lowest common multiple of 8 and 5 which is 40.

Therefore, 2 3/8 + 6 4/5 would be:

= 2 15/40 + 6 32/40

= 8 47/40

= 9 7/40

Since the answer gotten is 8 12/40. This is wrong.

c. 3 3/7 + 4 2/3 = 7 2/21

First and foremost, we need to know the lowest common multiple of 7 and 3 which is 21.

Therefore, 3 3/7 + 4 2/3 would be:

= 3 9/21 + 4 14/21

= 7 23/21

= 8 2/21

Since the answer gotten is 7 2/21. This is wrong.

d. 4 5/6 + 5 5/7 = 9 10/13

First and foremost, we need to know the lowest common multiple of 6 and 7 which is 42.

Therefore, 4 5/6 + 5 5/7 would be:

= 4 35/42 + 5 30/42

= 9 65/42

= 10 23/42

This is wrong as the answer gotten is 9 10/13

Therefore, the true option is

3 3/9+7 6/11 = 10 87/99

7 0
3 years ago
Help me with my test pls
JulijaS [17]

Answer:

The answer will be 40!!!!!!!!!!

8 0
3 years ago
1. An outdoor art is a metal cube with edge length 39 feet. What is the volume of the cube in feet? In cubic yard? ( Can someone
Law Incorporation [45]
The volume of a cube is just the side length cubed...

V=s^3  in this case:

V=39^3=59319 ft^3  

and in cubic yards it is:

59319 ft^3*(yd^3/27 ft^3)=2197 yd^3
5 0
3 years ago
Given: Elmwood St. and Oak Dr. are the same distance. All intersections are perpendicular.
vlabodo [156]

Answer:

The above result is proved with the help of Pythagoras theorem and explained below.

Step-by-step explanation:

Given figure ABCD in which AD=BC and all angles intersect at right angle. Hence, the triangle formed inside ADC and ABC are right angled triangle.

In triangle ADC,

By applying Pythagoras theorem, we get

AC^{2}=AD^{2}+DC^{2}    →  (1)

In triangle ABC,

AC^{2}=AB^{2}+BC^{2}    →  (2)

Now, from eq (1) and (2)

Peach Tree Dr. is the same distance as Sycamore Ln.


AD^{2}+DC^{2} = AB^{2}+BC^{2}

⇒ DC^{2} = AB^{2}              (∵ AD=BC)

⇒ DC=AB                    (∵Distance can never negative)

Therefore, Peach Tree Dr. is the same distance as Sycamore Ln.


8 0
3 years ago
What is the value of (f-3)?
almond37 [142]

Simply substitute the value of

3

given. In other words,

f

(

3

)

is the function of

f

(

x

)

, however, in this case,

x

is

3

f

(

3

)

=

3

(

3

)

−

4

Distribute

3

through the parenthesis

f

(

3

)

=

9

−

4

Simplify

f

(

3

)

=

5

8 0
3 years ago
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