Sulfur dioxide has a molecular formula of SO2. The balanced
chemical reaction leading to this isas shown below:
<span>S + O2 --->
SO2</span>
Therefore this means that 1 mole of sulfur and 1 mole of O2
reacts to form 1 mol of sulfur dioxide.
Assuming 1 mol of O2 and 1 mol of S for the sake of
calculation, therefore:
mass oxygen, O = (1 mol O2) (2 mol O/ 1 mol O2) (16 g O/
mol O) = 32 g O
mass sulfur, S = 1 mol (32 g / mol) = 32 g
Therefore the ratio of O to S is:
O:S = 32 g O / 32 g S = 1 g O2/ 1 g S
<span>Hence, there is 1 g of oxygen per 1 g of sulfur in sulfur
dioxide.</span>
your answer is Option B
there are 90 elements found naturally so option B statement is incorrect
HOPE THIS WILL HELP YOU
Answer:
oxidation takes place at the anode while reduction takes place at the cathode.
Explanation:
In the process of electrolysis the electric current is passed accross an ionic compound, the compound could either be in it's molten state or dissolved in a solvent. When there is connection between the anode and cathode are by a wire, there is always a flow of electrons from anode to cathode.
A redox reaction reffers to a chemical reaction in which there are both process of oxidation and the process of reduction i.e loss of election and gain of electrons occured simultaneously.
During the process of electrolysis, there is oxidation of an ion at anode which is the negative charged electrode, reduction as well takes occur at cathode which is the positively charged electrode at the same time.
solution:
Calculate the molar concentration of the polycyclic aromatic hydrocarbon(PHA)(178.23g/mol),that was found in a well water sample at a concentration of 6.21ppb.Assume the density of the water is 1.00mg/mL