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3 years ago

10

I need some one to do this fast!!!

1 answer:

Kruka [31]3 years ago

7 0

It’s 8 u cross multiply 7 and 1 then 1 and 56 and then divide 56 by 7

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For health reasons, Sarah needs to limit her fat intake to 25% of the total calories consumed in a day. If the fat intake is 550

8090 [49]

550 * 4 = 2200

Hope this helps !

4 0

3 years ago

Read 2 more answers

The first term of an arithmetic sequence is-3 and the 15 term is 53. What is the common difference of the sequence?

Annette [7]

$a_2=a_1+d$
$a_3=a_2+d=a_1+2d$
$a_4=a_3+d=a_1+3d$
...
$a_{15}=a_1+14d$

Since $a_1=-3$ and $a_{15}=53$ , the common difference $d$ is

$53=-3+14d\implies d=4$

6 0

3 years ago

The value of k so that the sequence k-1, k+3, 3k-1 forms an arithmetic progression is?

VashaNatasha [74]

Answer:

k = 4.

Step-by-step explanation:

An arithmetic sequence has a common difference.

So for this to be arithmetic:

k + 3 - (k - 1) = 3k - 1 - (k + 3)

k + 3 - k + 1 = 3k - 1 - k - 3

3 + 1 = 2k - 4

4 + 4 = 2k

k = 4.

The sequence is 3, 7, 11.

3 0

4 years ago

The width of a rectangle is 5 units less than the length. The area of the rectangle is 6 units. What is the width, in units, of

Readme [11.4K]

Answer:

The width of rectangle is 1 unit.

Step-by-step explanation:

Given:

The area of rectangle is 6 units and its width is 5 units less than the length.

So, to find the width of rectangle.

Let the length be $x$ and the width be $x-5$ .

Now, to find the width we put the formula of area of rectangle:

Area = length × width

$6= x\times (x-5)$

$6=x^{2}-5x$

$0=x^{2}-5x-6$

$0=x^{2}-6x+x-6$

$0=x(x-6)+1(x-6)$

$0=(x-6)(x+1)$

<em>On solving equation we get:</em>

$x-6=0, x+1=0$

Therefore, we take the value x=6 as it is positive value:

$x-6=0$

$x=6$

So, the width of rectangle:

Width = $x-5$

= $6-5$

= $1$

Therefore, the width of rectangle is 1 unit.

8 0

3 years ago

barxatty [35]

Sorry if I’m wrong but I think the answer is x= -3 11/20
Decimal form: x=-3.55

3 0

2 years ago