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Novay_Z [31]
3 years ago
14

The product of (4z^2 + 7z - 8) and (-z + 3) is -4z^3 + xz^2 + yz - 24. What is the value of x? What is the value of y?

Mathematics
2 answers:
ycow [4]3 years ago
8 0

Answer:

x=5+\frac{29}{z}-\frac{y}{z}

y=5z+29-xz

Step-by-step explanation:

Given: (4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24

Let's move everything we can to the left side of the equation. Some things will cancel out.

5z^2+29z=xz^2+yz

Now, let's move the term that includes x to the left side of the equation. Everything else should be moved to the right.

-xz^2=-5z^2-29z+yz

Let's get rid of the negative sign in front of x by dividing both sides by -1.

xz^2=5z^2+29z-yz

To get x completely isolated, divide both sides by z^2.

\frac{xz^2}{z^2}=\frac{5z^2}{z^2}+\frac{29z}{z^2}-\frac{yz}{z^2}

Simplify.

x=5+\frac{29}{z}-\frac{y}{z}

Let's solve for y. We will start with the distributed and simplified equation to make it easier.

5z^2+29z=xz^2+yz

Now, let's move the term that includes y to the left side of the equation. Everything else should be moved to the right.

-yz=-5z^2-29z+xz^2

Again, let's get rid of the negative sign in front of the y by dividing both sides by -1.

yz=5z^2+29z-xz^2

To isolate y, divide both sides by z.

\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}

Simplify.

y=5z+29-xz

snow_tiger [21]3 years ago
6 0

Answer:

x = 5

y = 29

Step-by-step explanation:

Edge Answer

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