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3 years ago

6y - 9y - 4 = -2y - 2 Solve for y Please give step-by-step answer and explaination.

1 answer:

Ivan3 years ago

8 0

Step 1. Subtract the 6y-9y which will give you -3y-4
Step 2. Add 4 to both sides, which will give you -4y = -2y +2
Step 3. Add 2y to the other side, which will
Give you -2y = 2
Step 4. Divide both sides by -2, which will give you -1

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3/5n+15=10+2/5n what is n

Nutka1998 [239]

$\textsf{Hey there!}$

$\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}$

$\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}$

$\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}$

$\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}$

$\textsf{Solve\ the set we have left over}$

$\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}$

$\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}$

$\mathsf{\dfrac{1}{5}n+15-15=10-15}$

$\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }$

$\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }$

$\mathsf{10-15=-5}$

$\mathsf{New\ equation: \dfrac{1}{5}n=-5}$

$\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}$

$\mathsf{\dfrac{1}{5}n\times5=5\times-5}$

$\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \ it \ gives \ us \ 1}$ $\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}$

$\mathsf{n =5\times-5}\\\mathsf{5\times-5 = -25}$

$\textsf{Thus, \underline{\bf{n = -25}}}\checkmark$

$\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\bf{n =-25}}}}}}\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

7 0

3 years ago

Jane does a total of 75 push-ups each week. How many push-ups will Jane do in the 12 weeks? (Show your work).

dedylja [7]

Answer:

900 push-ups

Step-by-step explanation:

75 push-ups in one week

In 12 weeks = 75 × 12 = 900 push-ups

PLEASE DO MARK ME AS BRAINLIEST IF MY ANSWER IS HELPFUL :) 

7 0

3 years ago

Indicate in standard form the equation of the line through the given points. P(0, -4), Q(5.1)

Elan Coil [88]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf P(\stackrel{x_1}{0}~,~\stackrel{y_1}{-4})\qquad Q(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{0}}}\implies \cfrac{1+4}{5}\implies \cfrac{5}{5}\implies 1$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{1}(x-\stackrel{x_1}{0})\implies y+4=x \\\\\\ y=x-4\implies -x+y=-4\implies x-y=4$