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PolarNik [594]
3 years ago
15

What is another way to write the ratio 3 to 10 ?

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0
I think its 3:10, I haven't done ratios in a while.

Hope this helped :)
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2 years ago
Bottles filled by a certain machine are supposed to contain 12 oz of liquid. In fact the fill volume is random with mean 12.01 o
stepan [7]

Answer:

27.43% probability that the mean volume of a random sample of 144 bottles is less than 12 oz.

Step-by-step explanation:

To solve this problem, it is important to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 12.01, \sigma = 0.2, n = 144, s = \frac{0.2}{\sqrt{144}} = 0.0167

What is the probability that the mean volume of a random sample of 144 bottles is less than 12 oz

This is the pvalue of Z when X = 12

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{12 - 12.01}{0.0167}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743.

So there is a 27.43% probability that the mean volume of a random sample of 144 bottles is less than 12 oz.

4 0
3 years ago
A Mexican restaurant sells quesadillas in two sizes: a "large" 10 inch-round quesadilla and a "small" 5 inch-
elena-14-01-66 [18.8K]

Answer:

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^2

where

r is the radius

step 1

Find the area of the 10 inch-round quesadilla

we have

D=10\ in

r=10/2=5\ in

substitute

A=\pi (5)^2

A=25\pi\ in^2

step 2

Find the area of the 5 inch-round quesadilla

we have

D=5\ in

r=5/2=2.5\ in

substitute

A=\pi (2.5)^2

A=6.25\pi\ in^2

step 3

Which is larger, half of the 10-inch quesadilla or the entire 5-inch quesadilla?

Compare

half of the 10-inch quesadilla is equal to ----> \frac{1}{2}(25\pi)=12.5\pi\ in^2

the entire 5-inch quesadilla ---->6.25\pi\ in^2

therefore

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

3 0
2 years ago
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