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3 years ago

9

What is displayed on the console when running the following program?

Computers and Technology

1 answer:

uranmaximum [27]3 years ago

7 0

I guess there should be the program code in your question. I presume that the complete version of your question is the following:

What is displayed on the console when running the following program?

public class Test {

public static void main(String[] args) {

try {

System.out.println("Welcome to Java");

int i = 0;

int y = 2 / i;

System.out.println("Welcome to HTML");

}

finally {

System.out.println("The finally clause is executed");

}

}

}

A. Welcome to Java, then an error message.

B. Welcome to Java followed by The finally clause is executed in the next line, then an error message.

C. The program displays three lines: Welcome to Java, Welcome to HTML, The finally clause is executed, then an error message.

D. None of the above.

Answer to the complete question with explanation:

B. Welcome to Java followed by The finally clause is executed in the next line, then an error message

After entering <em>try/catch</em> block program will output <em>"Welcome to Java"</em>.

Then <em>ArithmeticException</em> will be raised at line:

<em>int y = 2 / i;</em>

The reason is division by <em>0</em> because <em>i = 0</em>.

After that <em>finally</em> clause will be executed despite exception thrown which will output <em>"The finally clause is executed"</em>.

There could be a chance that you have modified answers to your question. In that case:

Answer to the original question:

a. Welcome to Java,

c. The finally clause is executed, then an error message.

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