Which conditional statement is true?

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e.

zaharov [31]

Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:_Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________QuQuestion

Show that for a square Question Question

Show that for a square symmetric matrix M, Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________tric mQuestion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________atrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________estion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:__________________

3 0

3 years ago

The function h(t) = −5t2 + 20t shown in the graph models the curvature of a satellite dish: graph of parabola starting at zero c

ipn [44]

Answer:

Part 1) Option B: 0 ≤ x ≤ 4

Part 2) Option C: (5x − 1)(2x − 3)

Part 3) Option C: The crop yield decreased by 10 pounds per acre from year 10 to year 20.

Part 4) Option B: f(x) = (2x + 1)(2x − 1)

Part 5) Option A: The company earned 85 billion dollars in 2008

Part 6) Option C: (3, 0) and (5, 0)

Step-by-step explanation:

Part 1) we have

$h(t)=-5t^{2}+20t$

This is a vertical parabola open downward

The vertex is a maximum

The x-intercepts are the points (0,0) and (4,0)

The vertex is the point (2,20) ---> The x-coordinate of the vertex is the midpoint of the x-intercepts

so

The domain is the interval ----> [0,4]

$0\leq t\leq 4$

The range is the interval ----> [0,20]

$0\leq h(t)\leq 20$

Part 2) we have

$V=10x^{2} -17x+13$

where

x is the time in minutes

V is the volume in gallons

we know that

When the trough is empty, the volume is equal to zero

so

For V=0

$10x^{2} -17x+3=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$10x^{2} -17x+3=0$

so

$a=10\\b=-17\\c=3$

substitute in the formula

$x=\frac{-(-17)(+/-)\sqrt{-17^{2}-4(10)(3)}} {2(10)}$

$x=\frac{17(+/-)\sqrt{169}} {20}$

$x=\frac{17(+/-)13} {20}$

$x=\frac{17(+)13} {20}=\frac{3}{2}$

$x=\frac{17(-)13} {20}=\frac{1}{5}$

so

$10x^{2} -17x+3=10(x-\frac{3}{2})(x-\frac{1}{5})$

simplify

$10(x-\frac{3}{2})(x-\frac{1}{5})=(2x-3)(5x-1)$

Part 3) we have

$f(x)=-x^{2}+20x+100$

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

In this problem we have

$f(a)=f(10)=-(10)^{2}+20(10)+100=200$

$f(b)=f(20)=-(20)^{2}+20(20)+100=100$

$a=10$

$b=20$

Substitute

$\frac{100-200}{20-10}$

$-\frac{100}{10}=-10$ ----> is a decreasing function

therefore

The crop yield decreased by 10 pounds per acre from year 10 to year 20.

Part 4) we have

$f(x)=4x^{2} -1$

<em>Find out the x-intercepts</em>

Remember that the x-intercepts are the values of x when the value of the function is equal to zero

so

For f(x)=0

$4x^{2} -1=0$

Solve for x

$4x^{2}=1$

$x^{2}=\frac{1}{4}$

take square root both sides

$x=(+/-)\frac{1}{2}$

so

$f(x)=4x^{2} -1=4(x-\frac{1}{2})(x+\frac{1}{2})=(2x-1)(2x+1)$

Part 5) we have

$t^{2}+14t+85$

Remember that

The y-intercept of a function is the value of the function (output value) when the value of x (input value) is equal to zero

In this problem

The expression represent a company's net sales, in billions, from 2008 to 2018

t is the number of years since the end of 2008

so

For t=0 -----> represent the end of 2008

$(0)^{2}+14(0)+85=85\ billion\ dollars$

therefore

The company earned 85 billion dollars in 2008.

Part 6) What are the x-intercepts of the parabola?

we have the points (2,3),(4,-1),(6,3)

This is a vertical parabola open upward

The vertex represent a minimum

In this problem the vertex is the point (4,-1)

The equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^2+k$

where

a is a coefficient

(h,k) is the vertex

we have

(h,k)=(4,-1)

substitute

$y=a(x-4)^2-1$

take the point (2,3) and substitute in the quadratic equation to solve for a

For x=2, y=3

$3=a(2-4)^2-1$

$3=4a-1$

$4a=4$

$a=1$

The quadratic equation is

$y=(x-4)^2-1$

Find out the x-intercepts

Remember that the x-intercepts are the values of x when the value of the function is equal to zero

so

For y=0

$(x-4)^2-1=0$

Solve for x

$(x-4)^2=1$

take square root both sides

$(x-4)=(+/-)1$

$x=4(+/-)1$

$x=4+1=5\\x=4-1=3$

therefore

The x-intercepts are the points (3,0) and (5,0)

7 0

3 years ago

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What is the slope in this graph?

fredd [130]

The slope of this graph is 6

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2 years ago

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How do I do this table !!!

erma4kov [3.2K]

Answer:

Step-by-step explanation:

just mutiply 120 by 1,2,3,4,5,6,7,8

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3 years ago

How do you put 5.96 as a fraction

Genrish500 [490]

5.96 into a fraction = 596/100 or 149.25

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3 years ago