Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
B.(6,5)
Step-by-step explanation:
because (6,5) ang sagot
No, its D
Just look at the rounds mentioned and subtract the scores from higher round with lower round.
Look at A: round 2 score - round 1 score = -2?
-3 -1 = -4 change, not -2 change so it is wrong
Look at B: round 3 score - round 1 score =-1?
-2-1 =-3 change, not -1 change so it is wrong
Look at C: round 3 score - round 2 score =-1?
-2 -(-3) = 1 change, not -1 change so it is wrong
Look at D: round 3 score - round 1 score =-3?
-2-1 = -3 change, matches with -3 so it is correct.
Answer:
M=-3
Step-by-step explanation:
Slope:
y2-y1/x2-x1
-3-3/1+1=6/-2=-3
Answer:
its the second one lol its just asking you to pick the one less than a and a is 0.11 so it would be 0.0019
Step-by-step explanation:
