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stiks02 [169]
4 years ago
13

Nicholas drew a triangle with 45°, 35°, and 100° angles. Is there another triangle with the same three angles but different side

lengths?
Mathematics
1 answer:
Mice21 [21]4 years ago
3 0

Answer:

Yes, there are infinite similar triangles with the same three angles and different side lengths

Step-by-step explanation:

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

There are infinite similar triangles with the same three angles and different side lengths

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What is the unit price for a piece of cheese if 3.25 pounds costs $19.50?
Stolb23 [73]

Answer:

$6

Step-by-step explanation:

divide 19.50 by 3.25

3 0
3 years ago
Mr. Pham wrote the equation below on the board. 18 - 7x = -20.5 What is the value of x?
slavikrds [6]
Use the arithmetic operations to get the variable x on one side of the equation and everything else on the opposite side.

If something is being is being done to a variable, we undo that operation by using the inverse of that operation.

For example, if 10 is being added to x, we use the inverse of addition or subtraction.

18 - 7x = -20.5

We variable x is being multiplied by 7 and is subtracting 18. We need to undo all those operations.

18 - 7x = -20.5
-7x = -38.5

Now the variable is only being multiplied by -7. Reverse the operation.

-7x = -38.5
x = 5.5

So, x is equal to 5.5.
7 0
3 years ago
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If 3 1/2 pounds of bananas cost $0.98, how much would one pound cost?
Yuki888 [10]
Divide .98 by 3 1/2. 3 1/2 in decimal form is 3.5 so .98 ÷ 3.5 = .28

So one pound of bananas would cost <span>$0.28</span>
4 0
3 years ago
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Which of these relations is a function?
marishachu [46]

Answer: C

Step-by-step explanation:

3 0
3 years ago
Estimate the area under the curve f(x) = x2 + 1 from x = 0 to x = 6 by using three circumscribed (over the curve) rectangles. An
BaLLatris [955]
1) split the range in three identical invervals of size [6 - 0] / 3 = 2

2) form three rectangles

2a) First rectangle: base 2, height f(2) = 2^2 + 1 = 5

     area 1 = base * height = 2 * 5 = 10

2b) second rectangle: base 2, height f(2+2) = 4^2 + 1 = 17

     area 2 = 2 * 17 = 34

2c) third rectangle: base 2 height f(4+2) = 6^2 + 1 = 37

     area 3 = 2*37 = 74

3) total area = area 1 + area 2 + area 3 = 10 + 34 + 74 =  118

3 0
3 years ago
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