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lukranit [14]
3 years ago
12

Simplity to create an equivalent expression 2 ( - 14+ r ) -(-3 - 5)

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

2r+25

Step-by-step explanation

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The average price of a 30 second commercial for the 2002 Super Bowl was $1,900,000. What was the price per second?
Tanzania [10]

Answer:

$63,333.33

Step-by-step explanation:

Divide 1,900,000 by 30 to get $63333.3333....which technically just rounds to $63333.33, and if you want to go further, $63333.

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2 years ago
I need help on this I will give brainlist help it will mean a lot this is my last math problem help me!​
Natalka [10]

Answer:

the second one

Step-by-step explanation:

i did it in my head and double checked :)

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Which of the following shows the graph of y = 2 l n x
Effectus [21]

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B.

Step-by-step explanation:

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There are 12 marbles in a box. 8 are purple, and 4 are green. What is the probability of picking a purple marble and then a gree
Bad White [126]

Answer: 8/33

Step-by-step explanation:

So the probability of picking a purple marble is 8/12, after that there are 11 marbles left in the box

Now the probability of picking a green marble without placing the first marble back is 4/11

So the probability of doing both is 8/12 x 4/11 = 8/33

8 0
2 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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