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Nimfa-mama [501]
3 years ago
11

Car travels 100 m in 5 seconds. What is the speed the car?

Mathematics
2 answers:
amm18123 years ago
8 0
To figure this question out, we simply must do a little division and multiplication. I see that you've given the conversion rate of miles to meters, so I assume that the car travels 100 METERS per 5 seconds, rather than 100 miles per 5 seconds. Now, we can take the 100 meters and divide by 5 to figure out how many meters is traveled per second. 100 divided by 5 is obviously 20, very easy division. Now, here comes the large numbers. We know that 3600 seconds is in an hour, so we can do 20 meters times 3600 seconds to find out how many meters is traveled per hour.


20 * 3600 = 72,000

Now that we have that number, we can convert the amount of meters traveled per hour (72,000) into miles. As listed above, 1 mile equals 1609 meters. So to convert, all we have to do is 72,000 divided by 1609.

72,000 / 1609 = 44.7

So there we have it, the answer is:

<span>D. 44.7 miles per hour
</span>
I hope this cleared up any confusion you may have been having.

- Sofie


weqwewe [10]3 years ago
4 0
How you do this is using the formula speed = distance/time. So this is 100/5 which is 20 meters a second. Using the conversion factor (can google "20 meters per second is how many mile") 20 meters a second = 44.7 miles per hour.

In conclusion, the answer you're looking for is D. 44.7 miles per hour.
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Answer:

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

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So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

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1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

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pvalue of Z when X = -1.5

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Z = \frac{0.496 - 0.494}{0.002}

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