All of them could be as A would be an equilateral B,C,D would be irregular triangles and 3 would be an Isosceles triangle but if you had to go with one it would be A
Hey there!
In this picture, we have many pairs of adjacent angles:
1 and 2
2 and 4
4 and 3
3 and 1
This is because these pairs are being connected by a vertex and a side.
Hope it helps and have a great day!!!
As per your question, total cost of watermelon should end with either 5(for odd quantity) or 0(for even quantity).
If the quantity of watermelon is odd, then the total cost value of pineapple should end with 3 and this is not possible when the cost of pineapple is ₹7.
So let's come to conclusion that the count(quantity) of watermelon should be any one of 0, 2, 4, 6.
If count of watermelon is 6: It will cost ₹30 and for remaining ₹8, we can buy 1 pineapple but still ₹1 will not be utilised. So 1 pineapple is not possible
If count of watermelon is 4: It will cost ₹20 and for remaining ₹18, we can buy 2 pineapple with ₹4 not being utilised. So 2 pineapple is also not possible.
If count of watermelon is 2: It will cost ₹10 and for remaining ₹28, we can buy 4 pineapple with all amount being utilised. We can buy 4 pineapple along with with 2 watermelon for ₹38.
If count of watermelon is 0: It will cost you ₹0 and for remaining ₹38, we can buy 5 pineapple with ₹3 being not utilised. So 5 pineapple is also not possible.
So the answer is 4 pineapple.
N+n<8
is that what you are looking for?
If you would like to solve the inequality 12 * p + 7 > 139, you can do this using the following steps:
12 * p + 7 > 139
12 * p > 139 - 7
12 * p > 132 /12
p > 132/12
p > 11
The correct result would be p > 11.
