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sukhopar [10]
3 years ago
9

Find the following trigonometry values cos (150*) = ? sin (150*) = ?

Mathematics
2 answers:
Vlad1618 [11]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

cos150°

= - cos(180 - 150)°

= - cos30°

= - \frac{\sqrt{3} }{2}

-------------------------

sin150°

= sin (180 - 150)°

= sin30°

= \frac{1}{2}

melisa1 [442]3 years ago
4 0

Answer:

See below in bold.

Step-by-step explanation:

cos 150 = - cos(180 - 150)

= - cos 30

= -√3/2.

sin 150

= sin (180 - 150

= sin 30

= 1/2.

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rewona [7]

Answer:

Option 2: (1,0) is the correct answer

Step-by-step explanation:

Given inequality is:

y>-5x+3

In order to find which point is solution to the given inequality we'll put the point one by one in the inequality. If the point satisfies the inequality, then the point is the solution of the inequality.

Putting (0,3) in inequality

3 > -5(0)+3\\3>0+3\\3>3

Putting (1,0) in inequality

0>-5(1)+3\\0>-5+3\\0>-2

Putting (-3,1) in inequality

1 > -5(-3)+1\\1> 15+1\\1>16

Putting (-1,-2) in inequality

-2>-5(-1)+3\\-2>5+3\\-2>8

The inequality is true for (1,0)

Hence,

Option 2: (1,0) is the correct answer

4 0
3 years ago
The manager of a neighborhood plant nursery measured the height of every tree on the lot. The mean height of the trees was 75 in
zloy xaker [14]

Answer: D. skewed to the right

Step-by-step explanation:

just took it

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%202x%2B31%3D5%7D" id="TexFormula1" title="\boxed{\sf 2x+31=5}" alt="\boxed{\s
AleksAgata [21]

2x + 31 = 5

2x = 5 - 31

2x = -26

x = -26/2

x = -13.

_______

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

3 0
3 years ago
Read 2 more answers
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
400 hundred thousand 13 thousand 11 hundreds and 4 ones in standard form
VikaD [51]
400,000,014,104

should be your answer

hope this helps
6 0
3 years ago
Read 2 more answers
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