The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
Answer:
x-8=8-x
x=8
y=8-8
y=0
Step-by-step explanation:
y=0
x=8
Answer:
147
Step-by-step explanation:
654 = 213 + 3x
-213 -213
441 = 3x
/3 /3
147 = x
Answer:
f(2) = 0
Step-by-step explanation:
Function f(t) is defined in three different ways depending on the value of t.
For t = 8, function f(t) is -64/t.
For t = 10, function f(t) is 14 - t.
We are not asked about f(8) or f(10). We are asked about f(2). The third definition of function f(t) is for all values of t that are not 8 or 10. 2 is not 8 or 10, so use the third definition of function f(t) and plug in 2 for t.
f(t) = t^2 - 3t + 2 for t not equal to 8 or 10.
f(2) = 2^2 - 3(2) + 2
f(2) = 4 - 6 + 2
f(2) = 0
