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3 years ago

Which quadratic function is represented by the table ???

Mathematics

1 answer:

Ulleksa [173]3 years ago

8 0

Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A. 3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 - 4 - 5

12 - 9

= 3

B. 3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

= 21

C. 2(-2)² + 3(-2) -5 =

2(4) - 6 - 5

8 - 11

= - 3

D. 2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

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Mr Wallace sells appliances in receives a weekly salary of $275 plus a 3% Commission on all of his self last week is sells total

Greeley [361]

Answer:

The total earning of Mr Wallace for the week is $310.37

Step-by-step explanation:

Given as :

The fixed weekly salary of Mr Wallace = $275

And The commission of 3% on his total sell

Last week Mr Wallace total sells amount= $1179

I.e 3% of total sells amount = 3% of $1179 = .03 × $1179 = $35.37

∴The total earning = $275 + $35.37 = $310.37

Hence The total earning of Mr Wallace for the week is $310.37 Answer

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3 years ago

Ryan owns three-eighths of a florist shop worth $76,000. What is the value of Ryan's shares of the business?

timofeeve [1]

3/8 of 76,000....." of " means multiply

3/8 * 76,000 = 228,000/8 = 28,500 <==

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3 years ago

For your last event of the day, you are going to purchase tickets to watch Patrick perform. They are charging people by the minu

timofeeve [1]

Answer:

$30

Step-by-step explanation:

Given that they charge $1 per minute to watch the show and in addition, there is also a processing fee that you must pay if $10, to attend the show for 20 minutes, it means that the total fee to be paid will be the sum of the product of 20 and $1 and the processing fee of $10

= (20 * $1) + $10

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2 years ago

On the first of each month, Shelly runs a 5k race. She keeps track of her times to track her progress. Her time in minutes is re

Vikki [24]

Answer:

C . 0.76

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan 40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32 June 34.28

July 35.38 Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean = $\frac{Sum \;of\;observations}{Total\;number\;of\;observations}$

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}$

Mean= $\frac{479.78}{12}$

Mean=39.982

Mean of the data excluding the outlier

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}$

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer Answer:

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan 40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32 June 34.28

July 35.38 Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean = $\frac{Sum \;of\;observations}{Total\;number\;of\;observations}$

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}$

Mean= $\frac{479.78}{12}$

Mean=39.982

Mean of the data excluding the outlier

Mean= $\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}$

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer :C . 0.76

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3 years ago

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aleksandrvk [35]

First you need to put the equation into slope form which is y = mx + b

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y = 1.5x + 1

In this equation the y-intercept is 1 and the slope is 1.5 or 3/2.

To graph the line you can start at the y-intercept then move up 3 and to the right 2 or down 3 and to the left 2.

Three points are (2, 4) , (-2 ,-2), (4, 7).

Hope this helps! Mark as Brainliest please! :)))

3 0

3 years ago

Read 2 more answers