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Hatshy [7]
3 years ago
7

8. Find the value of x to the nearest tenth. 7

Mathematics
1 answer:
3241004551 [841]3 years ago
5 0
Ok I think it would be 13 I think maybe
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WILL MARK BRAINLIEST HELP ASAP
OLga [1]
I’m not sure if this is right. But I think it’s 29

x=4
8(4) -3
32-3=29
4 0
3 years ago
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(sinA-cosA+1)/(sinA+cosA-1)=2(1+cosecA)​
borishaifa [10]

Answer:

The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

Step-by-step explanation:

Given Trigonometrical function as :

\frac{sin A - cos A + 1}{sin A + cos A - 1} = 2 (1 + cosec A)

Or, \frac{sin A + ( 1 - cos A)}{sin A - (1 - cos A)} = 2 (1 + cosec A)

,<u> Now, rationalizing </u>

\frac{(sin A + ( 1 - cos A)) \times (sin A + (1 - cosA))}{(sin A - (1 - cos A))\times (sin A + (1 - cos A))} = 2 (1 + cosec A)

Or, \frac{(sin A + (1 - cos A))^{2}}{sin^{2} - (1-cos A)^{2}} = 2 ( 1 + \dfrac{1}{\textrm sinA}

Or, \frac{sin^{2}A + (1 - cosA)^{2} + 2 \times sin A \times (1 - cos A)}{sin^{2}A - (1 + cos^{2}A - 2 cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - 1 - cos^{2}A +2 cos A} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - (sin^{2}A + cos^{2}A) - cos^{2}A +2 cos A} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{2- 2 cos A + 2 sin A - 2 sin A cos A}{- 2cos^{2}A +2 cos A} =  2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{1-  cos A +  sin A -  sin A cos A}{- cos^{2}A + cos A} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{(1-  cos A) +  sin A (1-cos A)}{cos A(1 - cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{(1-  cos A) (1 + sinA)}{cos A(1 - cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{(1 + sinA)}{(cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, sin A + sin² A = 2 cos A (1 + sin A)

Or,  sin A + sin² A = 2 cos A + 2 cos A × sin A

Or,   sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

So,The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0     Answer

6 0
3 years ago
A salesperson earns a commission based on the number and type of vehicle sold. A person selling 6 cars and 3 trucks earns $4,800
notsponge [240]

Answer:

C; $2,800

Step-by-step explanation:

Let the amount earned per truck sales be $t and the amount earned per car sales be $c

Selling 6 cars and 3 trucks earned a total of $4,800

This mathematically means;

6c + 3t = $4,800 •••••••••(i)

Selling 8 cars and 1 truck earned a total of $4,600

This mathematically means;

8c + t = $4,600 ••••••••(ii)

Now, we solve both equations simultaneously;

From equation ii, t = 4600 -8c

we plug this in equation i

6c + 3(4600-8c) = 4,800

6c + 13,800 - 24c = 4,800

18c = 9000

c = 9,000/18

c = 500

in second equation;

t = 4,600 - 8c

inputing the value of c, we have;

t = 4,600 -8(500)

t = 4,600 - 4,000

t = 600

Now we want to know how much commission earned on selling 2 cars and 3 trucks.

That will be 2c + 3t = 2(500) + 3(600) = 1000 + 1,800 = $2,800

8 0
3 years ago
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kifflom [539]
Y = 2/3x + 3 is the answer
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3 years ago
Evaluate the following expression with a calculator.
max2010maxim [7]

Answer:

hey guys join me

not for bad purpose

I'd - 702 041 7468

pass - 0819

for good purpose only

4 0
3 years ago
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