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3 years ago

8. Find the value of x to the nearest tenth. 7

Mathematics

1 answer:

3241004551 [841]3 years ago

5 0

Ok I think it would be 13 I think maybe

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I need more help with 21 questions

Mariulka [41]

Answer:

Step-by-step explanation:

9 ÷ 1/5

9 × 5/1

9 × 5

7 0

3 years ago

Read 2 more answers

Please help me and explain it please questions 28

klasskru [66]

Answer:

$1.35

Step-by-step explanation:

x: quarter=$0.25

y: dime=$0.10

z: nickel=$0.05

so total amount of changes

= (0.25*x)+(0.10*y)+(0.05*z)

x=3, y=5, z=2

substituting into the eqn

total = (0.25*3)+(0.10*5)+(0.05*2)

= 0.75 + 0.5 + 0.1

= $1.35

5 0

3 years ago

Read 2 more answers

Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$

So the total distance travelled is 1031 feet.

4 0

3 years ago

Is this correct? im just suspicious about every box being checked.

Anvisha [2.4K]

Answer:

yes, all of it is correct

Step-by-step explanation:

For the two triangles to be congruent, you would need the following angles and lengths to be congruent with each other.

6 0

3 years ago

Solve screen shot attachment EASY

Leona [35]

Answer:

$x = \frac{-3d-9}{k-d}$

Step-by-step explanation:

Step 1: Write out equation

d(-3 + x) = kx + 9

Step 2: Distribute <em>d</em>

-3d + dx = kx + 9

Step 3: Subtract 9 on both sides

-3d + dx - 9 = kx

Step 4: Subtract dx on both sides

-3d - 9 = kx - dx

Step 5: Factor out <em>x</em>

-3d - 9 = x(k - d)

Step 6: Divide both sides by k - d

$x = \frac{-3d-9}{k-d}$

8 0

3 years ago