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3 years ago

Don’t understand that problem

Mathematics

1 answer:

nata0808 [166]3 years ago

5 0

Answer:

(2c³ -20c² -10c) -(c² -40c +100)

Step-by-step explanation:

Profit

For a problem involving cost, revenue, and profit, you are expected to know that profit is the difference between revenue and cost. That is, if it costs you $2 to make a necklace you sell for $10, your profit is $10 -2 = $8.

Problem

The problem gives you polynomial expressions for revenue and cost, and asks you to combine them to make an expression for profit. In this first part, we simply show how we will combine them. (We presume a later part of the question will ask you to simplify the result.)

profit = revenue - cost

Substituting the given expressions, we have ...

profit = (2c³ -20c² -10c) -(c² -40c +100) . . . . . matches last choice

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3 years ago

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∆ABC is dilated using a scale factor of 12 to produce ∆A'B'C'.

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Answer:

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Step-by-step explanation:

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3 years ago

Hello can someone please help me on this :)

Zielflug [23.3K]

Answer:

Step-by-step explanation:

Find value of P that makes this true

4p-5=`9

Solve for P by isolating it on one side:

4p-5+5=9+5

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Translate the Algebraic Expression:

A waiter earns $128 for 6 hours of work including $86 of tips.

Subtract tips from total:

128-86=42

Divide Value between hours.

42/6=7

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Find the Value of X that makes this true

-4x+26=-2

Solve for X by isolating it on one side:

-4x+26-26=-2-26

-4x/-4=-28/-4

X=7

What is the first correct step in solving the equation:

33-2x=31

Subtract 33 from both sides

HOPE I HELPED!

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3 years ago

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9 × 1

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3 0

3 years ago

Match the parabolas represented by the equations with their foci.

Elenna [48]

Function 1 $f(x)=- x^{2} +4x+8$

First step: Finding when $f(x)$ is minimum/maximum
The function has a negative value $x^{2}$ hence the $f(x)$ has a maximum value which happens when $x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2$ . The foci of this parabola lies on $x=2$ .

Second step: Find the value of y-coordinate by substituting $x=2$ into $f(x)$ which give $y=- (2)^{2} +4(2)+8=12$

Third step: Find the distance of the foci from the y-coordinate
$y=- x^{2} +4x+8$ - Multiply all term by -1 to get a positive $x^{2}$
$-y= x^{2} -4x-8$ - then manipulate the constant of y to get a multiply of 4
$4(- \frac{1}{4})y= x^{2} -4x-8$
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is $12- \frac{1}{4}=11.75$

Hence the coordinate of the foci is (2, 11.75)

Function 2: $f(x)= 2x^{2}+16x+18$

The function has a positive $x^{2}$ so it has a minimum

First step - $x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4$
Second step - $y=2(-4)^{2}+16(-4)+18=-14$
Third step - Manipulating $f(x)$ to leave $x^{2}$ with constant of 1
$y=2 x^{2} +16x+18$ - Divide all terms by 2
$\frac{1}{2}y= x^{2} +8x+9$ - Manipulate the constant of y to get a multiply of 4
$4( \frac{1}{8}y= x^{2} +8x+9$

So the distance of focus from y-coordinate is $\frac{1}{8}$ to the north of $y=-14$
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: $f(x)=-2 x^{2} +5x+14$

First step: the function's maximum value happens when $x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25$
Second step: $y=-2(1.25)^{2}+5(1.25)+14=17.125$
Third step: Manipulating $f(x)$
$y=-2 x^{2} +5x+14$ - Divide all terms by -2
$-2y= x^{2} -2.5x-7$ - Manipulate coefficient of y to get a multiply of 4
$4(- \frac{1}{8})y= x^{2} -2.5x-7$
So the distance of the foci from the y-coordinate is - $\frac{1}{8}$ south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when $x=8.5$ and $y=79.25$ . The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when $x=-2.75$ and $y=-10.125$ . Manipulating coefficient of y, the distance of foci from y-coordinate is $\frac{1}{8}$ to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when $x=1.5$ and $y=9.5$ . The distance of the foci from the y-coordinate is $\frac{1}{8}$ to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

8 0

3 years ago