Answer:
equation;
Center (-4,2)
Radius is
Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of
Where (h,k) is center
r is the radius
So first we group like Terms together
Add 7 to both sides
Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem
and
so we have
To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is
So the radius is 3 times sqr root of 3.
2:3:1....added = 6
2/6(72) = 144/6 = 24
3/6(72) = 216/6 = 36
1/6(72) = 72/6 = 12
ratio is now 24:36:12
We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Given function : 3x−6y=12.
We are given x : −2 0 4.
We need to find the values of y's for x=-2, x=0 and x=4.
Plugging x=-2 in the given equation, we get
3(-2)−6y=12
-6 - 6y = 12.
Adding 6 on both sides, we get
-6+6 - 6y = 12+6
-6y = 18.
Dividing by -6 on both sides, we get
y= -3.
On the same way, plugging x=0.
3(0)−6y=12
-6y =12.
y=-2.
Plugging x=4,
3(4)−6y=12
12 -6y = 12.
Subtracting 12 on both sides.
12-12 -6y = 12-12
-6y=0
y=0.
Therefore,
<h3>x −2 0 4</h3><h3>y -3 -2 0</h3>
Answer:
x=61
Step-by-step explanation:
