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Ipatiy [6.2K]
2 years ago
9

You have two cubes that you fill with water to make ice cubes. the first cube has a side length of 3 units. the second cube has

a length of 5 units. write an expression that you can use to find the total volume of ice you can make.
Mathematics
1 answer:
nexus9112 [7]2 years ago
3 0
Please explain more briefly
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ryzh [129]
They are never perpendicular. They will be parallel and will never meet!  
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a local food company produces yogurt in 3/4 tab cups 2 cups= 1 pint 2 pints= 1 quart 4 quarts= 1 gallon 8 fl oz= 1 cup The tubs
miss Akunina [59]

Answer:

15cents.

Step-by-step explanation:

The cost of yogurt is $0.75

20% of this amount is the profit to the company

Profit = \frac{20}{100} * 0.75

          = $0.15

So the profit to the company is 15cents.

7 0
2 years ago
7.5% of what number is equal to 85% of 200?
Ksivusya [100]
Solving:

\frac{7.5}{100} *x =  \frac{85}{100} * 200

\frac{7.5x}{\diagup\!\!\!\!\!\!\!\!100} = \frac{17000}{\diagup\!\!\!\!\!\!\!\!100}
7.5x = 17000
x =  \frac{17000}{7.5}
x = 2266.6666... \:\to \boxed{\boxed{x \approx 2266.67}}\end{array}}\qquad\quad\checkmark
8 0
3 years ago
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How many sides does a polygon have if the sum of the interior angles is 900
sammy [17]

Answer:

there are 7 sides.

Step-by-step explanation:

hope this helped you

3 0
2 years ago
Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
2 years ago
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