Answer:
Going from left to right, 84, 31, 74, then 111 on top and 228 on bottom
Step-by-step explanation:
ANSWER
(3, 11) and (−3, −7)
EXPLANATION
The given system of equations are:

and

or

We equate the two equations to obtain,

We rewrite in standard quadratic form to obtain,

This simplifies to

We solve for x to obtain,




When


When x=-3,

Therefore the solution for the system is (3, 11) and (−3, −7).
Given:
The product of
and
greater than 5.
To find:
By how much the product of
and
greater than 5.
Solution:
First we need to find the product of
and
.




Now subtract 5 from the product.

Therefore, the product of
and
is 9.85 greater than 5.
Answer: Third degree polynomials are also known as cubic polynomials. Cubics have these characteristics: One to three roots. Two or zero extrema.
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