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Natalka [10]
3 years ago
15

Log(x+3/10)+logx+1=0

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0
Hi dear,

log(x+3)-log10+logx+1=0

log(x+3)-1+logx+1=0

log(x+3)+logx=0

logx(x+3)=0

x(x+3)=10^0

x^2+3x-1=0

solve this equation that answers are:

X1= [ (13)^(1/2) - 3]/2

X1= [ (13)^(1/2) + 3]/2

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So theres 366 days in a leap year, 
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2 years ago
Evaluate 5+\left(-3\right)-65+(−3)−65, plus, left parenthesis, minus, 3, right parenthesis, minus, 6.
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The question is not well-expressed, but it looks like you want to evaluate

5 + (-3) - 65 + (-3) - 65 + (-3) - 6

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So

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7 0
2 years ago
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