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givi [52]
3 years ago
15

The plot below shows the amount of time Mira spent on maths questions. If Mira had spent the same total amount of time, but spen

t an equal amount of time on each problem, how many minutes would each problem have taken?
Mathematics
1 answer:
just olya [345]3 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

Given

n = 5 --- number of questions

Required

The time spent on each question

The question has missing details, as the required plot to calculate the total time is not given.

However, the formula to use is as follows

Each = \frac{Total}{n}

Substitute 5 for n

Each = \frac{Total}{5}

Assume the calculated total time is 60 minutes; The equation becomes

Each = \frac{60}{5}

Each = 12\ mins

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a high school track teams long jump record is 21 feet and 2 1/4 inches. this year Tims best long jump is 20 feet and 9 1/2 inche
Alex787 [66]

Answer:

4.75 inches.

Step-by-step explanation:

We must introduce the symbols for inches and feet.

Here we will use, x' = x feet and x" = x inches

A high school track teams long jump record is 21 feet and 2\dfrac{1}{4} inches i.e. 21'2.25" this year.

Now, Tim's best long jump is 20 feet and 9\dfrac{1}{2} inches i.e. 20'9.5".

So, the difference between the record jump and Tim's best jump is

(21'2.25" - 20'9.5")

= (21'2.25" - 21') + (21' - 20'9.5")

= 2.25" + 2.5" {Since, 1' = 12" i.e. 21' = 20' 12"}

= 4.75"

Therefore, Tim has to jump 4.75 inches farther to break the record. (Answer)

3 0
2 years ago
A club sold $555 worth of
anastassius [24]

Answer:

111

Step-by-step explanation:

$555 ÷ $5 = 111

sorry I'm not good at explaining

6 0
3 years ago
Read 2 more answers
Which equation has a solution of x = -5?
lyudmila [28]
The first equation has a solution of X=-5
3 0
3 years ago
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Find the mean for the following sets of numbers.14,15,20,21
Jet001 [13]
The mean of those sets of numbers are 17.5
3 0
3 years ago
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PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

8 0
2 years ago
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