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AfilCa [17]
3 years ago
11

3y + 1 - 2y = -3 - 3y

Mathematics
2 answers:
Arada [10]3 years ago
7 0

Answer:

y=-1

Step-by-step explanation:

First you combine like terms.

1y+1=-3-3y

Then you add 3 on both sides so the -3 cancels out.

1y+4=-3y

Then you subtract 1y on both sides to cancel out y.

4=-4y

Then you divide both sides by -4 to get y by itself.

y=-1

s2008m [1.1K]3 years ago
3 0

Answer:

Step-by-step explanation:

3y + 1 - 2y = -3 -3y

4y = -4

y = -1

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2 years ago
Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

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