All categories

3 years ago

3y + 1 - 2y = -3 - 3y

Mathematics

2 answers:

Arada [10]3 years ago

7 0

Answer:

y=-1

Step-by-step explanation:

First you combine like terms.

1y+1=-3-3y

Then you add 3 on both sides so the -3 cancels out.

1y+4=-3y

Then you subtract 1y on both sides to cancel out y.

4=-4y

Then you divide both sides by -4 to get y by itself.

y=-1

s2008m [1.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

3y + 1 - 2y = -3 -3y

4y = -4

y = -1

You might be interested in

Explain how to create a graph to model the relationship between the 2 quantities in the table. A 2-column table with 4 rows. Col

azamat

Answer:

Sample Response:Use the values in the table to create ordered pairs. Label the x-axis with the independent variable, hours. Label the y-axis with the dependent variable, dollars. Plot the ordered pairs on the graph. If the variables can be represented as fractional parts you can draw a line from the origin that connects the points.

Step-by-step explanation:

I took one for the team D:

4 0

3 years ago

Let A be the set of all lines in the plane. Define a relation R on A as follows. For every l1 and l2 in A, l1 R l2 ⇔ l1 is paral

Lyrx [107]

Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

Given :

A be the set of all lines in the plane and R is a relation on set A.

$R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}$

To find :

Which type of relation R on set A.

Explanation :

A relation R on a set A is called reflexive relation if every $a\in A$ then $(a,a)\in R$ .

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if $(a,b)\in R$ then $(b,a)\in R$ for all $a,b\in A$ .

So, the relation R is a symmetric relation because if a line $l_1$ is parallel to the line $l_2$ the always the line $l_2$ is parallel to the line $l_1$ .

A relation R on a set A is called transitive relation if $(a,b)\in R$ and $(b,c)\in R$ then $(a,c)\in R$ for all $a,b,c\in A$ .

So, the relation R is a transitive relation because if a line $l_1$ s parallel to the line $l_2$ and the line $l_2$ is parallel to the line $l_3$ then the always line $l_1$ is parallel to the line $l_3$ .