WILL GIVE BRAINLIEST

OMG PLEASE HEEELLLPPPP ME PLEASE I WILL GIVE TONS OF POINTS.

Ivanshal [37]

Qwrtuioplkhgfsaaxxvbnmsbdheiwkkwbsbdne

6 0

2 years ago

Which shows one way to determine the factors of x3 11x2 – 3x – 33 by grouping? x2(x 11) 3(x – 11) x2(x – 11) – 3(x – 11) x2(x 11

Aloiza [94]

The one way to determine factors of x³ + 11x² – 3x – 33 will be $x^2(x+11)-3(x+11)_$ .

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The steps involved in the factorization are;

1. For each pair of parentheses, we create a common factor.

2. We use x2 as a common factor for the first parenthesis.

3. We use common factor 3 for the second parenthesis.

$x^3 + 11x^2 - 3x -33 \\\\ x^2(x+11)-3(x+11)_$

We will find the final solution as $x^2(x+11)-3(x+11)_$ .

Hence the one way to determine factors of x³ + 11x² – 3x – 33 will be $x^2(x+11)-3(x+11)_$ .

To learn more about the factorization refer to the link;

brainly.com/question/24182713

3 0

2 years ago

A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

2 years ago

Write the equation of the line that passes through the points (- 5, 1) and (2, 0) . Put your answer in fully reduced slope inter

Doss [256]

Answer:

y=-1/7x + 12/7

Step-by-step explanation:

Start by finding the slope

m=(1-0)/(-5-2)

m=-1/7

next plug the slope and the point (-5,1) into point slope formula

y-y1=m(x-x1)

y1=1

x1= -5

m=-1/7

y- 1 = -1/7(x - -5)

y-1=-1/7(x+5)

Distribute -1/7 first

y- 1=-1/7x + 5/7

Add 1 on both sides, but since its a fraction add 7/7

y=-1/7x + (5/7+7/7)

y=-1/7x+12/7

3 0

2 years ago

How do I figure this out?

Ilia_Sergeevich [38]

∠UXW = 36°

∠WZX = 66°

∠UWY = 48°

∠XYZ = 42°

Use the Alternate Exterior Angles Theorem. Always remember that a triangles angles add up 180°, so you can subtract the angles you already know in a triangle to figure out the remaining angle.

8 0

3 years ago