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3 years ago

14

Caroline is looking for a tool to measure the mass of a dictionary. Which tool should she use?

2 answers:

Yuri [45]3 years ago

6 0

Answer:

scale

Step-by-step explanation:

scales are used to measure weight

Deffense [45]3 years ago

4 0

Scale, hope this helps :)

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Brayden is working two summer jobs, making $21 per hour tutoring and making $10 per hour landscaping. In a given week, he can wo

BlackZzzverrR [31]

Answer:

I'm pretty sure it's 5 hours tutoring and 7 hours landscaping.

7 0

3 years ago

Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

3 years ago

Given the linear equation, y = 7x + 5:<br> A} Write an equation of a line parallel to this line.

Lana71 [14]

Answer:y = 7x + 5

Step-by-step explanation: does it matter which point it goes through?

8 0

3 years ago

If Trent has 11 quarters and dimes in his pocket, and they have a combined value of 200 cents, how many of each coin does he hav

allsm [11]

Answer:

Trent has 6 quarters and 5 dimes.

Step-by-step explanation:

Consider the provided information.

Let q = Number of quarters

d = Number of dimes.

Trent has 11 quarters and dimes.

$q+d=11$

$q=11-d$

The worth of a quarter is 25 cents.

The worth of a dimes is 10 cents

$25q+10d=200$

Substitute the value of q in above equation.

$25(11-d)+10d=200$

$275-25d+10d=200$

$15d=75$

$d=5$

Substitute the value of d in $q=11-d$

$q=11-5$

$q=6$

Hence, Trent has 6 quarters and 5 dimes.

4 0

3 years ago

I need help with this question ASAP

IRINA_888 [86]

Answer:

you would have to add 3 to 1 cuz there is a one with the x and since 3 is negative that how you would get y=-3x+1

Step-by-step explanation:

8 0

3 years ago