How many numbers containing the digits 2 AND 3 are in the interval [0,100]?
1 answer:
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The triangle height is calculated by Pythagorean Theorem
height^2 = 15^2 - 9^^2
height^2 = 225 - 81
height^2 = 144
height = 12
We can calculate the value of Angle a
cosine (a) = adj / hyp = 9/15 = .6
arc cosine (a) = 53.13 degrees
angle b = 180 -90 -53.13
angle b = 36.87 degrees
tangent b = height / x
tangent 36.87 = 12 / x
x = 12 / .75
x = 16
Yes, it's just that "simple" LOL
height^2 = 15^2 - 9^^2
height^2 = 225 - 81
height^2 = 144
height = 12
We can calculate the value of Angle a
cosine (a) = adj / hyp = 9/15 = .6
arc cosine (a) = 53.13 degrees
angle b = 180 -90 -53.13
angle b = 36.87 degrees
tangent b = height / x
tangent 36.87 = 12 / x
x = 12 / .75
x = 16
Yes, it's just that "simple" LOL
Answer:
We have the functions,
and
.
After plotting both the functions, we see that,
The graph of F(x) is given below, which has the y-intercept at (0,-1.5) and its horizontal asymptote is x-axis.
Also, the graph of f(x) is a straight line passing through (-4,0) and (0,2).
Further, we can see that the two graphs have intersection points as (-4.873,-0.436) and (2.873,3.436).
a. The probability of picking exactly two $10 bills is
b. The probability of picking at most one $5 bill is
<em><u>Explanation</u></em>
Number of $10 bills
and number of $5 bills
Total number of bills= 5+3 = 8. You need to randomly pick 4 bills, so the total possible outcome
<u>a. </u>
For getting exactly two $10 bills, you need to pick two $10 bills and two $5 bills. That means we will pick two $10 bill from 5 bills and two $5 bills from 3 bills.
So, the probability
<u>b.</u>
For getting at most one $5 bill, you need to pick <u>either zero or one</u> $5 bill.
If you pick <em>zero</em> $5 bill, that means there are <em>four</em><em> </em>$10 bills
and if you pick <em>one </em>$5 bill, that means there are <em>three </em>$10 bills.
So, the probability