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KATRIN_1 [288]
2 years ago
14

What is the area of a right triangle with a height of 8.9 and a base of 14.3?

Mathematics
1 answer:
svlad2 [7]2 years ago
5 0

Answer:

The area of a right angle triangle is A = 63.635

Step-by-step explanation:

<u>Step:-1</u>

By using area of the triangle formula is A = \frac{1}{2}(base)(height).......(1)

Given base of the triangle is (b) = 14.3

Given height of the triangle is (h) = 8.9

<u>Step:- 2</u>

substitute b and h values in formula in equation (1)

A = \frac{1}{2}(14.3)(8.9)

on simplification, we get the area of the triangle is 63.635

<u>Final answer</u>:-

The area of the triangle is A= 63.635

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In the proportion x/5= 15/3 which number is equal to x in the proportion? ​
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Answer:
x = 25
Step-by-step explanation:
We are given a word phrase:
In the proportion x over 5 equals 15 over 3 , which number is equal to x in the proportion?
So we will translate it to make it easier to solve.
Proportion x over 5 --->
equals ---> =
15 over 3 --->
Combining them, we get:

Solving this for x using cross multiplication:
6 0
2 years ago
What are the intercepts of this function f(x)=-8x+4
Sidana [21]

Answer:

Step-by-step explanation:

to find the x-intercept:

Make y=0

0=-8x+4

8x =4

x=4/8

x=1/2

to find y-intercept:

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y=-8(0) +4

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3 0
2 years ago
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Let f(x) = 6x-5 and g(x) = 2x-1. Find f • g
tankabanditka [31]

Hi

(6x-5) (2x-1) =  12x²-6x-10x+5 =  12x²-16x +5

3 0
3 years ago
Using the list below, what is the ratio of goats to the total number of animals at the zoo? Animals at a Petting Zoo Chickens 2
NemiM [27]

Answer:

Ratio of goat to total number of animals at the zoo = 2 : 5

Step-by-step explanation:

Chickens = 2

Deer = 4

Donkeys = 3

Goats = 6

Total animals at the zoo = 15

what is the ratio of goats to the total number of animals at the zoo?

Ratio of goat to total number of animals at the zoo = 6 : 15

= 6/15

= 2/5

Ratio of goat to total number of animals at the zoo = 2 : 5

3 0
2 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0&lt;×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
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