1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maria [59]
3 years ago
11

Simplify to create an equivalent expression.

Mathematics
1 answer:
Olin [163]3 years ago
8 0
<span>−y−3(−3y+5)
= </span><span>−y + 9y - 15
= 8y - 15

answer
</span><span>d.8y-15</span>
You might be interested in
Please assist me with these problems​
Vinil7 [7]

Part (a)

<h3>Answer: y1 and y3 are perpendicular</h3>

This is because the two slopes 2 and -1/2 multiply to -1. Perpendicular slopes multiply to -1 assuming neither line is vertical or horizontal.

=====================================================

Part (b)

Graph each line to see where they cross. The three points of intersection are

(0,4)

(2,-2)

(4,2)

The order of the points doesn't matter.

You could also form three systems of equations pairing up the equations, and solving each system. That way you can find the points of intersection. Graphing may be a better and faster route in my opinion. See the diagram below.

3 0
3 years ago
Read 2 more answers
Which letter represents (-2,3)?
Aleks [24]

Answer:

N represents (-2,3)

Step-by-step explanation:

x axis of N = -2

y axis of N = 3

5 0
2 years ago
Read 2 more answers
Expression equivalent to (0.28t-0.3)-(0.7t-0.28)?
Softa [21]
B because it obviously can’t be any other
3 0
3 years ago
1.
Alekssandra [29.7K]

Answer:

The number of visit so that both plan cost same is 10 .

Both the plan has equivalent choice of benefit

Step-by-step explanation:

Given as :

A gym has two membership plans.

For Gold plan

The charge per month = $50  

The charge per visit = $3

For Platinum plan

The charge per month = $20  

The charge per visit = $6

Let The number of visit for which each plan be same = n visits

Now, According to question

<u>∵ Each plan cost to be same</u>

So,

The charge per month for gold plan+ The charge per visit × numbers of visit = The charge per month for platinum plan+ The charge per visit × numbers of visit

I.e $50 + $3 × n = $20 + $6 × n

Or, $50 - $20 =  $6 × n  -  $3 × n

Or, $30 = ($6 - $3) × n  

Or, $30 = $3 × n  

∴ n = \dfrac{30}{3}

I.e n = 10

So, The number of visits = n = 10

Now, For Gold plan

The charge per month = $50  

The charge per visit = $3 × 10 = $30

So, Total charge for gold plan = $50 + $30 = $80

Similarly For Platinum plan

The charge per month = $20  

The charge per visit = $6×10 = $60

So, For Platinum plan ,total charge = $20 + $60 = $80

Hence, The number of visit so that both plan cost same is 10

and both the plan has equivalent benefit. Answer

4 0
3 years ago
5/6 divided by 3 2/3
Digiron [165]

Answer:1st number: 5/6, 2nd number: 3 2/3

5

6

÷

11

3

is

5

22

.

Steps for dividing fractions

Find the reciprocal of the divisor

Reciprocal of

11

3

:

3

11

Now, multiply it with the dividend

So,

5

6

÷

11

3

=

5

6

×

3

11

=

5 × 3

6 × 11

=

15

66

After reducing the fraction, the answer is

5

22

Mark brainlest

6 0
3 years ago
Other questions:
  • So Brandon has $987.00. She deposits $247.78. Then she cashes a check of 600.00 To a community beach for some new supply's. how
    13·2 answers
  • If two marbles are randomly selected from the bag without replacement, what is the probability that the first marble is blue?
    8·1 answer
  • 1.414213562 round to the nearest tenth
    12·2 answers
  • How many zeros does this equation have?
    6·2 answers
  • Help 10 Points PLEASE<br> AND Thank you
    11·1 answer
  • Evaluate 20/6 - 2/3. 2 1/6, 2 2/3, 3 1/3, 3 2/3
    7·1 answer
  • Can someone me with this question please ​
    14·2 answers
  • Anyone can help me with math for solving for a side in the right triangles for khan academy
    12·1 answer
  • Can y’all please help me
    8·1 answer
  • Which inequality is true?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!