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earnstyle [38]
3 years ago
8

99 POINTS

Mathematics
2 answers:
Alik [6]3 years ago
6 0

Answer:

  -a^2 - a + 12

Step-by-step explanation:

You only need to find the products of the first and last terms to determine the correct answer:

  (-a)(a) = -a^2

  (3)(4) = 12

You're looking for an expression with -1 as the leading coefficient and +12 as the constant. There is only one choice like that:

  -a^2 - a + 12

Viktor [21]3 years ago
4 0

Answer:   -a^2 - a + 12

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Identify the form of quadratic. *<br> f (x) = 2x2 – 5x + 7
TiliK225 [7]

Answer: The answer is -x+7

Step-by-step explanation:

Multiply the numbers 2 * 2=4

=4x-5x+7

Add similar evidence 4x + -5x =-x

-x+7

8 0
3 years ago
The circumference of a circle is 60 cm. What is the diameter
Mariana [72]
<h2>d ≈ 19.1 cm</h2>

<em>Using the formulas</em>

<em>C = 2πr</em>

<em>d = 2r</em>

<em>Solving for 'd' (diameter)</em>

<em>d = C</em>

<em>π = 60</em>

<em>π ≈ 19.09859cm</em>

<em />

7 0
2 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
14. (10pts) Consider the outward flux || Fonds where F = [01: 1, 2 ] and the surface S is the portion of the
grin007 [14]

Answer:

3y+3b

Step-by-step explanation:

6 0
2 years ago
Annie’s change purse contained 5 quarters 8 dimes and 8 nickels if Annie chose 2 coin randomly without replacing them in her pur
Bogdan [553]
<h3>Answer:</h3>

2/15

<h3>Explanation:</h3>

There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.

Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.

_____

<em>Comment on nCk</em>

The number of ways to choose k objects from n, when order does not matter, is ...

... n!/(k!(n -k)!)

For the computations above, we have ...

... 8C2 = 8·7/(2·1) = 28

... 21C2 = 21·20/(2·1) = 210

8 0
3 years ago
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