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3 years ago

What is the solution to the equation 3/5(x+4/3) = 1.04

Mathematics

1 answer:

sveta [45]3 years ago

6 0

Answer:

2. 0.4

Step-by-step explanation:

Solve for "x" by simplifying both sides of the equation, then isolating the variable.

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You have a pet hamster and a pet mouse. The hamster weighs 416 of a pound. The mouse weighs 116 of a pound. How much more does t

Harrizon [31]

How much more does the hamster weighs than the mouse is 300 pounds.

Since we have a pet hamster and a pet mouse. We know that the hamster weighs 416 of a pound and the mouse weighs 116 of a pound.

To know how much more the hamster weighs more than the mouse, we take the difference between the weight of the hamster and the weight of the mouse.

Since the weight of the hamster = 416 pounds and the weight of the mouse equals 116 pounds.

<h3>The difference in weight</h3>

The difference in the weight d = weight of hamster - weight of mouse

= 416 pounds - 116 pounds

= 300 pounds.

So, how much more does the hamster weighs than the mouse is 300 pounds.

Learn more about difference here:

brainly.com/question/751620

4 0

2 years ago

Help please im lost and not good in math

Damm [24]

Answers: a = 49
b = 10
c = 105

8 0

3 years ago

Read 2 more answers

How can I simplify/rewrite the 1st(top) equation into the 2nd(Botton),please show a step by step solution.

Vaselesa [24]

Answer:

see below

Step-by-step explanation:

$-2(4 - \frac{x}{2} )^{5} + C$

Think of the above as:

$-\frac{2}{1}$ * $(\frac{8}{2} - \frac{x}{2} )^{5} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{2^{5}} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{32} + C$

= $-\frac{1}{1}$ * $\frac{(8 - x)^{5}}{16} + C$

= $\frac{-1(8 - x)^{5}}{16} + C$

= $\frac{(-8 + x)^{5}}{16} + C$

Can flip it around to be...

$\frac{(x - 8)^{5}}{16} + C$

4 0

3 years ago

I'll mark as brainliest if it lets me;-;<br>please answer B. & C. with solution:)

san4es73 [151]

Answer:

B. AC = 22, BC = 22, AB = 44

C. AC = 30, BC = 30, AB = 60

Step-by-step explanation:

$radius \: \overline {OR} \perp chord \: \overline {AB}$ at C. (given)

$\therefore AC = BC$ (perpendicular dropped from the center of the circle to the chord bisects the chord)

$\therefore 2x - 6 = x + 8$

$\therefore 2x - x= 6 + 8$

$\therefore x= 14$

$AC = 2x-6=2(14)-6=28-6= 22$

$BC= x + 8=14 + 8= 22$

AB = AC + BC = 22 + 22 = 44

$radius \: \overline {OR} \perp chord \: \overline {AB}$ at C. (given)

$\therefore BC = AC$ (perpendicular dropped from the center of the circle to the chord bisects the chord)

$\therefore 7x-5=4x+10$

$\therefore 7x - 4x= 5 + 10$

$\therefore 3x= 15$

$\therefore x= \frac{15}{3}$

$\therefore x= 5$

$AC = 4x+10=4(5)+10=20+10= 30$

$BC= 7x - 5=7(5)-5=35-5= 30$

AB = AC + BC = 30 + 30 = 60

7 0

3 years ago

Please help. It’s due today

vladimir1956 [14]

Answer:

There's nothing there I believe you forgot to add a link just add or create another question and i'll see what I can do :)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers