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4 years ago

Help me with 12, 13, and 14 please ! thanks

Mathematics

1 answer:

melamori03 [73]4 years ago

3 0

When squaring fractions, both the numerator and the denominator are squared:

12. (4/5)² = 16/25

13. (-5/12)² = 25/144

14. (13/6)² = 169/36

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I need help on how to do this

Leni [432]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

a) A system of equations has no solutions when the graphs of those equations do not intersect. If the equations are equations of a line, then the lines must be parallel in order for them not to intersect.

Any parallel line will do.

b) There is one solution when the graphs intersect in exactly one point.

Any line that crosses the one shown will do.

c) There are infinite solutions when the graphs describe the same curve.

A line overlapping the one shown is the one you want.

5 0

3 years ago

Solve x/2 - 8 = y for x

Nookie1986 [14]

Answer:

B) x=2y + 16

Step-by-step explanation:

First, you'd multiply the x/2 by 2 to get x by itself.

You do the same throughout the whole equation.

Then isolate the x by getting rid of the -16 to the other side by adding 16

Your final answer should be:

B) x=2y + 16

3 0

3 years ago

On a coordinate plane, triangles P Q R and S T U are shown. Triangle P Q R has points (4, 4), (negative 2, 0), (negative 2, 4).

mamaluj [8]

Answer:

The answer is below

Step-by-step explanation:

Two triangles are said to be similar if their corresponding angles are equal and the corresponding sides are in proportion.

The distance between two points on the coordinate plane is given as:

$Distance=\sqrt{(x_2-x_1}^2+(y_2-y_1)^2 \\\\Therefore\ in\ triangle\ PQR:\\\\|QR|=\sqrt{(-2-(-2))^2+(4-0)^2}=4\\\\|PQ|=\sqrt{(-2-4)^2+(0-4)^2}=\sqrt{52}=2\sqrt{13} \\\\|PR|=\sqrt{(-2-4)^2+(4-4)^2}=6$

In triangle STU:

$|ST|=\sqrt{(-1-2)^2+(-2-(-4))^2}=\sqrt{13}\\\\|SU|=\sqrt{(-1-2)^2+(-4-(-4))^2} =3\\\\|TU|=\sqrt{(-1-(-1))^2+(-4-(-2))^2}=2$

|QR| / |TU| = 4/2 = 2

|PR| / |SU| = 6/3 = 2

|PQ| / |ST| = 2√13 / √13 = 2

Hence:

|QR| / |TU| = |PR| / |SU| = |PQ| / |ST|

Therefore, △PQR and △STU are similar triangles since the ratio of their sides are in the same proportion.

6 0

3 years ago

Read 2 more answers

Fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5

liubo4ka [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we know that the solution of the following equation

$ax^2+bx+c=0$

are

$\dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \ \text{ when } \Delta=b^2-4ac \geq 0$

<em>I would suggest that you try to apply this formula first and check the solution only after you try.</em>

Let's apply it in this case, we have:

$a=4\sqrt{5} \\ \\ b=-24 \\ \\ c= -9\sqrt{5}$

$\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ \sqrt{\Delta}=36 \ \text{ and the solutions are } \\ \\ \\ x_1=\dfrac{24-36}{8\sqrt{5}}=\dfrac{-12}{8\sqrt{5}}=\boxed{\dfrac{-3}{2\sqrt{5}}} \\ \\x_2=\dfrac{24+36}{8\sqrt{5}}=\dfrac{60}{8\sqrt{5}}=\boxed{\dfrac{15}{2\sqrt{5}}}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

4 years ago

if 300 jellybeans cost you x dollars. how many jellybeans can you purchase for 50 cents at the same rate?

Furkat [3]

It is 125 jelly beans

5 0

4 years ago