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2 years ago

Math pls help it says there is a cone but there isn't.

Mathematics

2 answers:

Snezhnost [94]2 years ago

7 0

Answer:

SA = π3^2 + π3(7.5)

Step-by-step explanation: r is radius and L

is r*l/2

so 3*5/2=15/2=7.5

seriously look at a problem more carefully and memorise your formulas!

Oksanka [162]2 years ago

6 0

Answer:

pi*r^2+pi^r^l

Step-by-step explanation:

ik you already got it in the comments but im putting it here for other people so it is quick to get

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Landon used a semicircle, a rectangle, and a right triangle to form the figure below. Which is the best estimate of the area of

Damm [24]

Answer:

38.28cm^2

Step-by-step explanation:

Area of rectangle = 24cm^2

Area of rectangle = 8cm^2

Area of semicircle = 6.28cm^2

4 0

4 years ago

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PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

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1 year ago

Katrina is asked to simplify the expression .

Lorico [155]

The property of distribution

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4 years ago

Read 2 more answers

Which one would it be and why.

SVETLANKA909090 [29]

Answer:B because its the rule in algebra that you must gave 1 as a zero

Step-by-step explanation:

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3 years ago

WILL GIVE BRAINIEST! Triangle ABC is isosceles with AB = BC. If AC = 20 and {ABC} = 240, then find the perimeter of triangle ABC

dolphi86 [110]

Answer:

Step-by-step explanation:

Since the triangle's area is 240, the base * height must equal 480 because for the area of a triangle it is half of that. Since you know that the base AC = 20, find out what you can multiply by 20 to get 480. This gives you a result of 24. Now that the height is found divide the triangle into two right triangles. Now Just use the pythagorean theorem to find the legs of the triangles. AB = BC = 26. 26 + 26 + 20 = 72 which is the perimeter.

4 0

3 years ago

Math pls help it says there is a cone but there isn't.​

Math pls help it says there is a cone but there isn't.