There are 63 students in the room, this is because 21 time 3 gives you 63.
I believe it will be 36 Im sorry if im wrong.
Answer:
Step-by-step explanation:
a1=2/3
sequence is 2/3,3/4,4/5,...
for numerator a1=2
d=3-2=1
numerator of nth term=a1+(n-1)d=2+(n-1)×1=2+n-1=n+1
denominator = 1 more than numerator=n+1+1=n+2
so an=(n+1)/(n+2)
or for denominator a1=3,d=4-3=1
denominator of nth term=3+(n-1)×1=3+n-1=n+2
an=(n+1)/(n+2)
First Divide both sides by -5.73
-5.73q/-5.73=97.41/-5.73
Answer: q=-17
Answer:
![V = \pi r^2 h](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cpi%20r%5E2%20h)
And for this case the value for the height is
the diameter is provided
so then the radius is given by:
![r = \frac{D}{2}=\frac{8.1 in}{2}= 4.05 in](https://tex.z-dn.net/?f=%20r%20%3D%20%5Cfrac%7BD%7D%7B2%7D%3D%5Cfrac%7B8.1%20in%7D%7B2%7D%3D%204.05%20in)
Then we can find the volume with the first formula and replacing we got:
![V = \pi (4.05in)^2 (10.7 in)= 551.4 in ^3](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cpi%20%284.05in%29%5E2%20%2810.7%20in%29%3D%20551.4%20in%20%5E3)
The final answer for this case would be 551.4 cubic inches
Step-by-step explanation:
The volume for a right circular cone is given by this formula:
![V = \pi r^2 h](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cpi%20r%5E2%20h)
And for this case the value for the height is
the diameter is provided
so then the radius is given by:
![r = \frac{D}{2}=\frac{8.1 in}{2}= 4.05 in](https://tex.z-dn.net/?f=%20r%20%3D%20%5Cfrac%7BD%7D%7B2%7D%3D%5Cfrac%7B8.1%20in%7D%7B2%7D%3D%204.05%20in)
Then we can find the volume with the first formula and replacing we got:
![V = \pi (4.05in)^2 (10.7 in)= 551.4 in ^3](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cpi%20%284.05in%29%5E2%20%2810.7%20in%29%3D%20551.4%20in%20%5E3)
The final answer for this case would be 551.4 cubic inches