A car was bought in 2009 for $120000. it 2016 it value decrease by 20%. it's value decrease by 10% of it's value in 2010.fond th

Question

3 years ago

7

e value of the car at the end of 2011.
guys I am giving you 100 points do answer me with solution.
and I will mark you as brainlest. BYE!BYE!

2 answers:

Romashka [77] · Answer 1 · 2022-06-09T17:08:16+03:00

6 0

Answer:

<h2>This is the case % decrease</h2><h2>120000*80/100*90/100</h2><h2>=12*80*90</h2><h2>=7200*12</h2><h2>=72000+ 14400</h2><h2>=86400 rs</h2>

Step-by-step explanation:

Mariana [72] · Answer 2 · 2022-06-09T18:59:15+03:00

Price of car in 2009 = $120000

Value decreased by 20 % in 2010

⇒ Price of car in 2010 = $120000 - (20% of $120000)

= $120000 - ( (20/100) × 120000 )

= $120000 - $24000 = $96000

Value again decreased by 10 % in 2011

⇒ Price of car in 2011= $96000 - (10% of $96000)

= 96000 - ((10/100) × 96000 )

= 96000 - 9600 = $86400

So value of car at end of 2011 is $86400

I hope this is correct.

I hope this helps you and who ever else happens to see this.