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3 years ago

The question is in the photo please helpp

Mathematics

2 answers:

MariettaO [177]3 years ago

7 0

I am pretty sure it is -8 but someone else should confirm my answer.

zloy xaker [14]3 years ago

5 0

-8 is the answer. I hope this is correct.

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the perimeter of the square is 15 1/7 meters.Find the length of each side, and has a picture of a square

ElenaW [278]

Thats all the question?

6 0

3 years ago

I'm almost done if ur up

nirvana33 [79]

Answer:

1/4 gallon

Step-by-step explanation:

the least number that has at least one x is 1/4

5 0

1 year ago

Lydia wanted to flip a coin and roll a die at the same time, but she also wondered what the probability of the coin landing on h

exis [7]

Answer:

incorrect

Step-by-step explanation:

this is because it would be 1/2 and 1/6. you would have to multiply the bases for a probability of 1/12

7 0

3 years ago

One number is 4 times as large another. The sum of their reciprocals is 45/4. Find the two numbers

Reptile [31]

Let,
the numbers be "x" and "y"
According to the question,
x = 4y ......................................................equation (1)

$\frac{1}{x} + \frac{1}{y}= \frac{45}{4}$ ...................................equation (2)

Taking equation (2)
$\frac{1}{x} + \frac{1}{y}= \frac{45}{4}$

Substituting the value of "x" from equation (1), we get,

$\frac{1}{(4y)} + \frac{1}{y}= \frac{45}{4}$

$\frac{1}{4y} + \frac{1}{y}* \frac{4}{4} = \frac{45}{4}$

$\frac{1}{4y} + \frac{4}{4y}= \frac{45}{4}$

$\frac{1+4}{4y} = \frac{45}{4}$

$\frac{5}{4y} = \frac{45}{4}$

Cross multiplying, we get,

$5*4 = 45*4y$

$20 = 180y$
<u />
$\frac{20}{180} = y$

$\frac{1}{9} = y$

$y = \frac{1}{9}$

Now,
Taking equation (1)
x = 4y
Substituting the value of "y", we get

$x = 4( \frac{1}{9} )$

$x= \frac{4}{9}$

So, the numbers are $\frac{1}{9}$ and $\frac{4}{9}$

7 0

2 years ago

Read 2 more answers

Find the range of the function F(x) = the integral from 0 to x of the square root of 4-t^2 dt

ioda

Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)

If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.

On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.

For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.

Then the range of F(x) is the interval [-π, π].

8 0

2 years ago