Let antonio's age = a and let sarah's age = s
2a + 3s = 34 (given in question)
s = 5a (given in question)
Because we know that s = 5a, we can replace it with 5a in the first equation to give this:
2a + 3(5a) = 34
∴ 2a + 15a = 34
∴ 17a = 34
∴ a = 2
Therefore we can see that Antonio is 2. Because we have been told that Sarah is 5 times Antonio's age, we can say that Sarah is 10.
A.)5000.0085
.0-tenth place
.00-hundreth
.000-thousanth
Answer:
1 over 3 3/4 = 4 over 15
Step-by-step explanation:
First number 0.6
second number 7/9 = 0.77
If we take other number as x, it would be between 0.6 and 0.77
there are infinite numbers between 0.6 and 0.77.
0.6 < x < 0.77
Answer:
33
Step-by-step explanation:
7x3=21
4x3=12
21+12=33
