It is a 3-4-5 right triangle
leg1 := 3x, leg2:=4x, hypotenuse:=5x
given hypotenuse = 75m
=> 5x=75
So, x= 75÷5 = 15
Therefore, leg1 = 3(15) = 45m.
leg2= 4(15) = 60m.
Let's say the side length of square A is x, which means the side length of square B is 2x.
Then, the area of square A can be written as , and the area of square B can be written as .
There's no diagram here with shaded region, so I'll just find the area of square A as a percentage of the area of square B:
= 1/4 = 25%
So, the answer is 25% (note this is the answer to the question: "express the area of square A as a percentage of the area of square B; there is no diagram showing me where the shaded area is, so I cannot answer the original question
Answer: B. (Leah did not have to provide collateral.)
Answer:
A
Step-by-step explanation:
The only option with multiplication represented is A.
Answer:
Write a cosine equation with the following properties: Amplitude: 3. Period: 2pi. Midline: 2. Phase shift: 4 units shifted left. In the form of: y=a cos b(x-h) +k.
