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allochka39001 [22]
3 years ago
14

3(2R-7)=6 I need help on finding this

Mathematics
1 answer:
goblinko [34]3 years ago
4 0

3(2R-7)=6

3(2R-7)=6 >>>>> 6R=27

>>>> R = 27/6 = 4 1/2

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What Is the solution to the system of equations? Y=-3x-2<br> 5x+2y=15
snow_tiger [21]

Answer:

x,y=-19,55

Step-by-step explanation:

plug in y.

5x+2(-3x-2)=15

5x-6x-4=15

-x=19

x=-19.

Plug in.

y=-3(-19)-2

y=55

correct is B.

Hope this helps :D

3 0
3 years ago
Find the midpoint of the segment with the following endpoints. (7,−2) and (1,−10)
Zinaida [17]

Answer:

The answer is

<h2>(4 \:  , \:  - 6)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M  = ( \frac{x1 + x2}{2} ,  \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(7,−2) and (1,−10)

The midpoint is

<h3>M = ( \frac{7 + 1}{2}   ,  \:  \frac{ - 2 - 10}{2} ) \\  = ( \frac{8}{2} , \:  -  \frac{12}{2} )</h3>

We have the final answer as

<h3>(4 \:  , \:  - 6)</h3>

Hope this helps you

3 0
3 years ago
A phone company charges $.25 for the first minute of a long distance call and $.07 for each addition minute. write an equation t
Mamont248 [21]

The cost C of a long distance call as a function of the length t is C(t) = 0.25 + 0.07t and the number of minutes is 25 minutes

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

<h3>How to determine the solution to the system?</h3>

A system of linear equations is a collection of at least two linear equations.

In this case, the given parameters are:

Charge for first minute = $.25

Rate for additional minute = $.07 per minute

Let the number of minutes be t and the total cost be C(t)

So, we have:

C(t) = Charge for first minute + Rate for additional minute * x

This gives

C(t) = 0.25 + 0.07t

When the total cost is $2, the equation becomes

0.25 + 0.07t = 2

Subtract 0.25 from both sides

0.07t = 1.75

Divide both sides by 0.07

t = 1.75/0.07

Evaluate the quotient

t = 25

Hence, the number of minutes is 25 minutes

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

6 0
1 year ago
mr.masons height is at most 4 inches more than twice his daughters height.Mr.masons height is 70 inches
nadezda [96]
M < = 2d + 4
m = 70

70 < = 2d + 4
70 - 4 < = 2d
66 < = 2d
66/2 < = d
33 < = d...or d > = 33

so the daughter is at least 33 inches

4 0
3 years ago
Read 2 more answers
What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

5 0
3 years ago
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