Question

What is the of the base of the cone below if the height is 8 and the volume is 54

Answer 1

Answer:

Base radius: $r=\sqrt{6.45}$

Step-by-step explanation:

Considering the cone is Right Circular Cone:

Volume of the cone =  $\pi *r^2*\frac{h}{3}$

$r=radius \\\\h=height$

Given :  

$Volume=54\\\\Height =8$

Putting in the formula:

                            $54=3.14*r^2*\frac{8}{3} \\\\ 54=\frac{25.12}{3} *r^2$

Multiply by '3' both sides:

                           $54*3=25.12*r^2\\\\162=25.12*r^2$

Divide by '25.12' both sides:

                           $r^2=\frac{162}{25.12}$

                            $r^2=6.45$

                         $r=\sqrt{6.45}$

So, the cone has base radius: $r=\sqrt{6.45}$