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Ahat [919]
3 years ago
8

Side AC and side BD are perpendicular bisectors of each other. Find BC and DB

Mathematics
2 answers:
Westkost [7]3 years ago
8 0
The answer is BC=13 and DB=24
Mandarinka [93]3 years ago
7 0

Answer:

(C)BC = 13, DB = 24

Step-by-step explanation:

It is given that Side AC and side BD are perpendicular bisectors of each other, then from the figure, we have

DE=EB=12(Side AC and side BD are perpendicular bisectors of each other)

Now, from ΔBEC, we have

(BC)^2=(BE)^2+(EC)^2

=(12)^2+(5)^2

=144+25

=169

Therefore, BC=\sqrt{169}=13

Thus, BC=13

Also, DB=DE+EB

DB=12+12

DB=24

Therefore,  BC = 13, DB = 12

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lbvjy [14]

Answer:

47.8°

Step-by-step explanation:

Let's first outline the important parameters

--- <V = 90°

Vt = 64

UV = 43

The angles in a triangle sums up to 180,but we don't have up to 2 angles given so as to find the third one. What we have to is to find the second angle,in this case T,using the sine rule.

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(Sin 90)/64 = sin t/43

Cross multiply and we have

43 sin 90 = 64 sin t

Sin t = 43 sin 90 ÷ 64

Sin t = 0.6719

Sine inverse of t = 42.2°(the second angle)

Angle U = 180 -( 90 + 42.2)

180 - 132.2

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