Question

A heterozygous tall pea plant is allowed to self-fertilize. The resulting F1 progeny are 25% homozygous tall, 50% heterozygous tall and 25% dwarf. If all of the F1 plants are allowed to self-fertilize, what percentage of the F2 progeny are dwarf?

Answer 1

Answer:

25% heterozygous tall

Explanation:

If we take the F1 generation as parents and let them self-fertilise, we have 4 crosses.

The first one for homozygous tall, then we have 100% AA.

The second and third one for heterozygous tall and we have 25% AA, 50%Aa and 25%aa for each of them.

The last one would be for dwarf, and we'll have 100%aa.

Adding all of them, we'll have

AA = 100 + 25 + 25 = 150%

Aa =  50+50 = 100%

aa = 100 + 25 + 25 = 150%

as we had 4 crosses, so dividing the total percentages by 4, we'll have,

AA = 37.5%

Aa = 25%

aa = 37.5%

:. The percentage of heterozygous tall would be 25%.

Hope it helps:)