One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:
And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees
Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel
Answer:
21 plants are in the garden
Step-by-step explanation:
here , base = 7 m
height = 24 m
Thus , The area of the triangle (garden ) is 84 m ²
he wants 4 plants for each square meter of area.
therefore , for 84 m ² number of plants are
i.e 21 plants
hence , 21 plants are in the garden
The answer is complex number
a complex number is 2 parts
1. the real part
2. the imaginary part
the real part is the 'a' part of the a+bi
the imaginary part is the 'bi' part of the a+bi
answer is A
(B means exponent is no higher than 1, C means exponent is 2, D means b^2-4ac)
answer is A
Answer:
73
Step-by-step explanation:
120-47=73 simple math
Without LCD :
1/2(4x + 6) = 1/3(9x - 24)
2x + 3 = 3x - 8
2x - 3x = -8 - 3
-x = - 11
x = 11
with LCD :
1/2(4x + 6) = 1/3(9x - 24) ...multiply by 6
3(4x + 6) = 2(9x - 24)
12x + 18 = 18x - 48
12x - 18x = -48 - 18
-6x = - 66
x = -66/-6
x = 11
Yes, the answers are the same :)
