Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
We want to calculate the following

Using the properties of exponents, we have that

So we have

So, if factor 10^-4 on the right side, we have

Note that

Then,

So we have that
Answer:
Its a Translation because all they did with it was move it. It never changed size or shape.
Step-by-step explanation:
Answer:
m=2
Step-by-step explanation:
I calculated it sorry