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3 years ago

Solve each system of equation Y=-3x+5 5x-4y=-3

1 answer:

6 0

Y = -3x + 5
5x - 4y = -3

   5x - 4(-3x + 5) = -3
5x + 4(3x) - 4(5) = -3
   5x + 12x - 20 = -3
   17x - 20 = -3
   + 20 + 20
      17x = 17
   17    17
      x = 1
      y = -3x + 5
      y = -3(1) + 5
      y = -3 + 5
      y = 2
      (x, y) = (1, 2)

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2. Given a directed line segment with endpoints A(3, 2) and B(6, 11), what is the point that

KATRIN_1 [288]

Answer:

The point of division is (5 , 8)

Step-by-step explanation:

* Lets explain how to solve the problem

- If point (x , y) divides the line whose endpoints are $(x_{1},y_{1})$

and $(x_{2},y_{2})$ at ratio $m_{1}:m_{2}$ , then

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

* Lets solve the problem

- The directed line segment with endpoints A (3 , 2) and B (6 , 11)

- There is a point divides AB two-thirds from A to B

∵ The coordinates of the endpoints of the directed line segments

are A = (3 , 2) and B = (6 , 11)

∴ $(x_{1},y_{1})$ is (3 , 2)

∴ $(x_{2},y_{2})$ is (6 , 11)

∵ Point (x , y) divides AB two-thirds from A to B

- That means the distance from A to the point (x , y) is 2/3 from

the distance of the line AB, and the distance from the point (x , y)

to point B is 1/3 from the distance of the line AB

∴ $m_{1}:m_{2}$ = 2 : 1

∵ $x=\frac{(3)(1)+(6)(2)}{2+1}=\frac{3+12}{3}=\frac{15}{3}=5$

∴ The x-coordinate of the point of division is 5

∵ $y=\frac{(2)(1)+(11)(2)}{2+1}=\frac{2+22}{3}=\frac{24}{3}=8$

∴ The y-coordinate of the point of division is 8

∴ The point of division is (5 , 8)

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2 years ago

There are 39 students sitting on the bleachers and 6 students sitting on the floor. What is the ratio of the number of students

Aleks [24]

Answer:

39;45

Step-by-step explanation:

students on the floor;total students

5 0

3 years ago

Read 2 more answers

PLEASE HELP:)

Debora [2.8K]

The first incorrect is the second step so choice B. ,bc. the exponents need assuming not multiply

hope helped

8 0

2 years ago

PLEASE HELP IM DOING SO BAD ALREADY I NEED A GOOD GRADE. In the square below, the four quarter-circles are congruent. Find the a

Neko [114]

I'm assuming a quarter-circle is exactly 1/4 of a circle. Thus if you have 4 congruent quarter-circles, that should mean they make a complete circle.

If that is the case, then we can find the area of the full circle using pi*r^2.

So the area of the circle is 5^2*pi or 25pi.

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3 years ago

Find the x- and y- intercepts of the graph of each equation. 2x+3y=6

Eva8 [605]

X = 3 that is you x intercept
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2 years ago