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d1i1m1o1n [39]
3 years ago
14

Solve each system of equation Y=-3x+5 5x-4y=-3

Mathematics
1 answer:
____ [38]3 years ago
6 0
Y = -3x + 5
5x - 4y = -3

   5x - 4(-3x + 5) = -3
5x + 4(3x) - 4(5) = -3
     5x + 12x - 20 = -3
             17x - 20 = -3
                   + 20  + 20
                    17x = 17
                     17     17
                        x = 1
                        y = -3x + 5
                        y = -3(1) + 5
                        y = -3 + 5
                        y = 2
                  (x, y) = (1, 2)
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A 2 quart container of window cleaner cost $6.96. What is the price per cup?
marissa [1.9K]

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$0.87

Step-by-step explanation:

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$6.96 ÷ 8 = $0.87

4 0
2 years ago
Read 2 more answers
Give an example of this when adding two rationalnumbers with different signs and provide the product.
kolezko [41]

ANSWER:

\begin{gathered} \frac{4}{5}+-\frac{8}{3}=-\frac{28}{15} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{32}{15} \end{gathered}

STEP-BY-STEP EXPLANATION:

Rational numbers are all numbers that can be expressed as a fraction, that is, as the quotient of two whole numbers.

Therefore, an example would be:

\begin{gathered} \frac{4}{5}\text{ and - }\frac{8}{3} \\ \text{adding} \\ \frac{4}{5}+-\frac{8}{3}=\frac{4}{5}-\frac{8}{3} \\ \frac{4}{5}-\frac{8}{3}=\frac{4\cdot3-5\cdot8}{5\cdot3}=\frac{12-40}{15}=-\frac{28}{15} \\ \text{ product} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{4\cdot8}{5\cdot3}=-\frac{32}{15} \end{gathered}

5 0
1 year ago
Solve de system by elimination. x-5y=3 4x-4y=12​
Anit [1.1K]

If we multiply the top equation by -4 we can get rid of the x so:

-4x+20y=-12

4x-4y=12

Add these up

16y=0

Y=0

X=3

7 0
3 years ago
By law, an industrial plant can discharge no more than 500 gallons of waste water per hour, on the average, into a neighboring l
lisabon 2012 [21]

Answer:

P = 0.0438 ; We reject the Null and conclude that there is significant evidence that the discharge limit per gallon of waste has been exceeded.

Due to the small sample size.

Step-by-step explanation:

H0: μ = 500

H1 : μ > 500

Test statistic :

(xbar - μ) / S.E

Tstatistic = (1000 - 500) / 200

= 500 / 200

= 2.5

Pvalue from Test score ; df = 4 - 1 = 3 ; using calculator :

Pvalue = 0.0438

At α = 0.05

Pvalue < α ; We reject the Null and conclude that there is significant evidence that the discharge limit per gallon of waste has been exceeded.

The test above has a very small sample size, and for a distribution to be approximately Normal, the sample size must be sufficiently large enough according to the Central limit theorem.

For a two sided analysis ; the Pvalue is twice that for the one sided, hence, Pvalue = (0.0438 * 2) = 0.0876 yielding a less strong evidence against the Null.

3 0
2 years ago
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