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Xelga [282]
3 years ago
9

A data set has 24 data points.

Mathematics
1 answer:
VikaD [51]3 years ago
6 0
Short Answers:

Question: How many points are above the median? 
Answer: 12

Question: How many points are below the 1st quartile?
Answer: 6

Question: How many points are between the first and third quartiles?
Answer: 12

=======================================

Explanations to how I got those answers:

We have 24 data points so half of them are below the median and the other half are above the median. Take half of 24 to get 24*(1/2) = 24*0.5 = 12
That's why there are 12 values above the median. 

Note: This trick only works if you have an even number of values. 

-----------------------

Q1 = first quartile
The first quartile is the median of set L, where L is the set of values lower than the median. We have 12 values in set L. Half of those values (6) are above Q1 and the other 6 values are below Q1. 

-----------------------

Q1 = first quartile
Q3 = third quartile
The interquartile range (IQR) spans from Q1 to Q3. This is exactly 50% of the distribution, or half of the values. We'll get the same answer as we did in the first part. So this is why there are 12 values between Q1 and Q3.
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Evaluate the expression: 16P4
Tju [1.3M]

The expression 16p⁴ will be written as (2p)⁴.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given expression will be solved as below:-

16p⁴  = ( 2 x 2 x 2 x 2)p⁴

16p⁴  = 2⁴ x p⁴

16p⁴  = ( 2p )⁴

Therefore, the expression 16p⁴ will be written as (2p)⁴.

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8 0
2 years ago
Please help!
katovenus [111]

Answer: f(3.5) = 58.20

Step-by-step explanation:

Wow...what degree of exponent are we to assume?

I'll go with 2 as we are only given two exemplars.

f(x) = x² + Ax + B

f(- 2.5) = 9 = (-2.5)² + (-2.5)A + B

f(2.5) = 45 = (2.5)² + (2.5)A + B

we can subtract the first equation from the second

45 - 9 = 2.5² - (-2.5)² + 2.5A - (-2.5A) + B - B

36 = 5A

A = 7.2

45 = (2.5)² + (2.5)7.2 + B

B = 20.75

F(3.5) = 3.5² + 7.2(3.5) + 20.75 = 58.2

6 0
3 years ago
Which of the following pairs of expressions could represent consecutive odd numbers?
iVinArrow [24]
N and n+2 because if n=1 then you do 1+2 and that equals 3. So then you have 1,3
3 0
4 years ago
After heating up in a teapot, a cup of hot water is poured at a temperature of 210°F. The cup sits to cool in a room at a temper
Fiesta28 [93]

Newton's Law of Cooling:

T(t)=T_{s}+(T_{o}-T_{s})e^{-kt}

T(t) = Temperature given at a time

t = Time

T_{s} = Surrounding temperature

T_{o}= Initial temperature

e = Constant (Euler's number) ≈ 2.72

k = Constant

Using this information, find the value of k, to the nearest thousandth, then use the resulting equation to determine the temperature of the water cup after 4 minutes.

First, plug in the given values in the equation and solve for k:

T(t) = 197°, t = 1.5 minutes, T_{s} = 70° and T_{o}= 210°  

T(t)=T_{s}+(T_{o}-T_{s})e^{-kt}\\197=70+(210-70)e^{-1.5k} \\197 -70 = (140)e^{-1.5k} \\127 =(140)e^{-1.5k}\\\frac{127}{140}=e^{-1.5k} \\ln(\frac{127}{140})=-1.5k\\-0.097=-1.5k\\0.0649 = k

k ≈ 0.065

Let the temperature of the water cup after t = 4 minutes be T(t) = x

Now, let's plug the new time and k constant in the equation and solve for x:

T(t)=T_{s}+(T_{o}-T_{s})e^{-kt}\\\\\x=70+(210-70})e^{-0.065*4}\\\\x=70+(140})e^{-0.26}, -0.26=-\frac{26}{100}=-\frac{13}{50} \\

x=70+(140})e^{-\frac{13}{50}}\\\\

x=70+(140})e^{\frac{1}{\frac{13}{50}}\\\\\\

x=70+e^{\frac{140}{\frac{13}{50}}\\\\\\

x=70+{\frac{140}{\sqrt[50]{e^{13}}}\\

x = 70 +\frac{140}{1.3} \\x=70+107.947\\

x=177.95 ≈ 178

Temperature of water after 4 minutes is 178°

sorry if there's any misspelling or wrong step but I hope my answer is correct ':3

3 0
3 years ago
Simplifying algebraic expressions<br> -8(-7t-2)+10(3-5t)
igomit [66]
Step one write down your equation
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8 0
3 years ago
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