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Paladinen [302]
4 years ago
5

Julio was making $20 an hour. His wage recently increased to $22 an hour. What was his percent of increase?

Mathematics
1 answer:
Tcecarenko [31]4 years ago
7 0
10% difference divided by original
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Re-write the quadratic function below in Standard Form?<br> y = –2(x + 4)(x - 3)
4vir4ik [10]

y = -2(x + 4)(x - 3)

y = -2(x² + x - 12)

y = -2x² -2x + 24

7 0
3 years ago
Find x, y<br><br> Please try to explain how you did it
BlackZzzverrR [31]
I believe this is scale factor? SF=new/old. 10/8= a scale factor of 1.25 (the image gets 1.25x bigger). To find x, multiply 5 by 1.25 and subtract the original length of 5 (you subtract this length because x is only the value of the new part of the triangle). X=6.25-5, X=1.25. Try to find y yourself using this scale factor. (Brainliest would be appreciated)
4 0
2 years ago
Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide
ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{\sigma}{\sqrt{n}}

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

7 0
3 years ago
What is the arithmetic mean of the following numbers?<br> 1,2, 10, 6, 4,4,6,3,1,4
sp2606 [1]

Answer:

The quadratic mean (rms) of a set of numbers is the square root of the sum of the squares of the numbers divided by the number of terms.











⎷

(

1

)

2

+

(

2

)

2

+

(

10

)

2

+

(

6

)

2

+

(

4

)

2

+

(

4

)

2

+

(

6

)

2

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Step-by-step explanation:

One to any power is one.

√

1

+

(

2

)

2

+

(

10

)

2

+

(

6

)

2

+

(

4

)

2

+

(

4

)

2

+

(

6

)

2

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Raise  

2

to the power of  

2

.

√

1

+

4

+

(

10

)

2

+

(

6

)

2

+

(

4

)

2

+

(

4

)

2

+

(

6

)

2

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Raise  

10

to the power of  

2

.

√

1

+

4

+

100

+

(

6

)

2

+

(

4

)

2

+

(

4

)

2

+

(

6

)

2

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Raise  

6

to the power of  

2

.

√

1

+

4

+

100

+

36

+

(

4

)

2

+

(

4

)

2

+

(

6

)

2

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Raise  

4

to the power of  

2

.

√

1

+

4

+

100

+

36

+

16

+

(

4

)

2

+

(

6

)

2

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Raise  

4

to the power of  

2

.

√

1

+

4

+

100

+

36

+

16

+

16

+

(

6

)

2

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Raise  

6

to the power of  

2

.

√

1

+

4

+

100

+

36

+

16

+

16

+

36

+

(

3

)

2

+

(

1

)

2

+

(

4

)

2

10

Raise  

3

to the power of  

2

.

√

1

+

4

+

100

+

36

+

16

+

16

+

36

+

9

+

(

1

)

2

+

(

4

)

2

10

One to any power is one.

√

1

+

4

+

100

+

36

+

16

+

16

+

36

+

9

+

1

+

(

4

)

2

10

Raise  

4

to the power of  

2

.

√

1

+

4

+

100

+

36

+

16

+

16

+

36

+

9

+

1

+

16

10

Add  

1

and  

4

.

√

5

+

100

+

36

+

16

+

16

+

36

+

9

+

1

+

16

10

Add  

5

and  

100

.

√

105

+

36

+

16

+

16

+

36

+

9

+

1

+

16

10

Add  

105

and  

36

.

√

141

+

16

+

16

+

36

+

9

+

1

+

16

10

Add  

141

and  

16

.

√

157

+

16

+

36

+

9

+

1

+

16

10

Add  

157

and  

16

.

√

173

+

36

+

9

+

1

+

16

10

Add  

173

and  

36

.

√

209

+

9

+

1

+

16

10

Add  

209

and  

9

.

√

218

+

1

+

16

10

Add  

218

and  

1

.

√

219

+

16

10

Add  

219

and  

16

.

√

235

10

Cancel the common factor of  

235

and  

10

.

Tap for fewer steps...

Factor  

5

out of  

235

.

√

5

(

47

)

10

Cancel the common factors.

Tap for fewer steps...

Factor  

5

out of  

10

.

√

5

⋅

47

5

⋅

2

Cancel the common factor.

√

5

⋅

47

5

⋅

2

Rewrite the expression.

√

47

2

Rewrite  

√

47

2

as  

√

47

√

2

.

√

47

√

2

Multiply  

√

47

√

2

by  

√

2

√

2

.

√

47

√

2

⋅

√

2

√

2

Combine and simplify the denominator.

Tap for fewer steps...

Multiply  

√

47

√

2

and  

√

2

√

2

.

√

47

√

2

√

2

√

2

Raise  

√

2

to the power of  

1

.

√

47

√

2

√

2

1

√

2

Raise  

√

2

to the power of  

1

.

√

47

√

2

√

2

1

√

2

1

Use the power rule  

a

m

a

n

=

a

m

+

n

to combine exponents.

√

47

√

2

√

2

1

+

1

Add  

1

and  

1

.

√

47

√

2

√

2

2

Rewrite  

√

2

2

as  

2

.

Tap for fewer steps...

Use  

n

√

a

x

=

a

x

n

to rewrite  

√

2

as  

2

1

2

.

√

47

√

2

(

2

1

2

)

2

Apply the power rule and multiply exponents,  

(

a

m

)

n

=

a

m

n

.

√

47

√

2

2

1

2

⋅

2

Combine  

1

2

and  

2

.

√

47

√

2

2

2

2

Cancel the common factor of  

2

.

Tap for more steps...

√

47

√

2

2

1

Evaluate the exponent.

√

47

√

2

2

Simplify the numerator.

Tap for fewer steps...

Combine using the product rule for radicals.

√

47

⋅

2

2

Multiply  

47

by  

2

.

√

94

2

The result can be shown in multiple forms.

Exact Form:

√

94

2

Decimal Form:

4.84767985

…

4 0
3 years ago
Ungkapkan perimeter pentagon, P dalam sebutan a,b dan c.​
sasho [114]

Answer:

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3 0
3 years ago
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