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sleet_krkn [62]
3 years ago
9

1+3x=-5+x

lt="1 + 3x = - 5 +x" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Oliga [24]3 years ago
4 0
Get all your variables on same side and solve x=-2
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Solve this please .......​
nikdorinn [45]

Answer:

The sum of reciprocals is 2/3.

You don't need complex numbers to solve this, but if you try to find a and b you will need complex numbers.

Step-by-step explanation:

a+b = 2

a*b = 3

1/a + 1/b = x

(a*b)*(1/a + 1/b) = (a*b)x

b + a = (a*b)(x)

2 = 3x

x = 2/3

b = 2 - a

a*(2 - a) = 3

-a^2 + 2a = 3

-a^2 + 2a - 3 = 0

a^2 - 2a + 3 = 0

let's solve the quadratic equation

a^2 - 2a + 3 = a^2 - 2a + 1 + 2 = (a - 1)^2 + 2 = 0

(a - 1)^2 = -2

a_1 - 1 = \sqrt{2}i\\a_1 = 1+\sqrt{2}i\\\\a_2 - 1 = -\sqrt{2}i\\a_2 = 1 - \sqrt{2}i\\

these options correspond to a and b from the original question.

8 0
3 years ago
In the inequality -4x > -16, your sign will stay the same because there are 2 negatives. True or False
snow_tiger [21]

Answer:

False

Step-by-step explanation:

If x is a negative number then it will stay the same. If it is a positive number then it depends.

8 0
3 years ago
you have 33 math and science problems for homework. you have 7 more math problems than science problems. how many problems do yo
Verdich [7]
You have 33 math problems and 26 science.
3 0
3 years ago
Read 2 more answers
a city worker is painting a stripedown the center of main street. main street is 8/10 mile long the worker painted 4/10 mile of
harina [27]
Subtract 8/10 from 4/10 but just the numerator (the top number) and you will get 4/10
8 0
3 years ago
Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.
Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

 The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

→a=2

Let , v be the corresponding eigenvector of the given eigenvalue.

→[a-I] v=0

→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

 We have to find solution of the system

→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

5 0
4 years ago
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