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sleet_krkn [62]
3 years ago
9

1+3x=-5+x

lt="1 + 3x = - 5 +x" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Oliga [24]3 years ago
4 0
Get all your variables on same side and solve x=-2
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Find the area of a floor which is covered by 1050 tiles.each tiles measuring 20 square meters​
RoseWind [281]

Answer:

area of floor is

1050*20=21000

Step-by-step explanation:

mark me as brainliest

7 0
2 years ago
In arithmetic sequence the first term is 5 and the common difference is 4. Determine the 6th term of sequence
Harlamova29_29 [7]

Answer:

The 6th term of the sequence is 25

Step-by-step explanation:

first term = a = 5

common difference = d = 4

The nth term of a sequence is

T_n = a + (n - 1)d

Therefore, the 6th term of the sequence is

T_6 = a + (6 - 1)d

T_6 = a + 5d

T_6 = 5 + 5(4)

T_6 = 5 + 20

T_6 = 25

3 0
3 years ago
A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
1 year ago
A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to th
Vladimir [108]

Answer:

The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}

Step-by-step explanation:

Given as :

The distance of blimp  (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = \frac{AC}{BC} = \frac{h}{d}

And sin Ф =  \frac{AB}{BC} = \frac{5500}{d}

∵, cos²Ф = 1 - sin²Ф

So, (\frac{h}{d})^{2} = 1 - (\frac{5500}{d})^{2}

Or, (\frac{h}{d})^{2} = (\frac{d^{2}- 5500^{2}}{d^{2}})

Or,                                     h² = d² - 5500²

∴                                        h = \sqrt{d^{2}- 5500^{2}}

Or,                                     h = \sqrt{(d + 5500) (d - 5500)}

Hence The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}     Answer

3 0
3 years ago
A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If
inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

(5+x)(10+x)=84

solve for x

Apply distributive property

50+ 5x+10x+x^2=84\\x^2+15x-34=0

solve the quadratic c equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+15x-34=0  

so

a=1\\b=15\\c=-34

substitute in the formula

x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}

x=\frac{-15\pm\sqrt{361}} {2}

x=\frac{-15\pm19} {2}

x=\frac{-15\pm19} {2}=2

x=\frac{-15\pm19} {2}=-17

therefore

The solution is x=2 ft

8 0
3 years ago
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