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Anna11 [10]
2 years ago
5

Two cars leave the same location traveling in opposite directions. One car leaves at 3:00 p.m. traveling at an average rate of 5

5 miles per hour. The other car leaves at 4:00 p.m. traveling at an average rate of 75 miles per hour. Let x represent the number of hours after the first car leaves.
How many hours after the first car leaves will the two cars be 380 miles apart?


Enter an equation that can be used to solve this problem in the first box.

Solve for x and enter the number of hours in the second box.
Mathematics
1 answer:
Misha Larkins [42]2 years ago
8 0

Answer:

1

Step-by-step explanation:

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8.) Mrs. Ruiz bought six 2-liter bottles of juice. How many dekaliters of juice
solong [7]
(B) because 1 litter is equal to .1 dekaliter
3 0
2 years ago
11,700 is invested in a compound interest account paying 3.9% compounded quarterly. How much will be in the account after 18year
Misha Larkins [42]
A=p(1+i/m)^mn
A=11,700×(1+0.039÷4)^(4×18)
A=23,527.94
8 0
3 years ago
The vertical of three squares are joined to form a right triangle , what is the area of the largest square
lakkis [162]

Answer:

43cm²

Step-by-step explanation:

let's first consider the area of a square.

the area is L² which means all sides are equal so we take the length times the breadth which is both equal because like we said all sides are equal.

so to find the side of the square using the area, we take the square root of both of the area.

\sqrt{25}  = 5

and also

\sqrt{18}  = 4.2

so we have the height of the triangle as 5cm and the base is 4.2cm.

now, from the triangle, since we have two sides and it's a right-angled, we can use Pythagoras' formula.

\sqrt{ {5}^{2}  +  {4.2}^{2} }  = 6.53cm

so the side 6.53cm is also the same side as the largest triangle. Since it's a square, all sides are equal. So we find the area of the largest triangle by using the formula

Area = L²

Area = 6.53²

Area = 42.6cm

the nearest cm square

Area = 43cm²

8 0
2 years ago
Read 2 more answers
(10.02)
ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

6 0
3 years ago
Write an addition equation with a positive addend and negative addend and a resulting sum of -8
Ierofanga [76]
-18 + 10 = -8

------------------------------------
7 0
3 years ago
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