Answer:
it should be 2462 feet³
Step-by-step explanation:
The complete question is
A fence must be built to enclose a rectangular area of 5000ft^2. Fencing material costs $1 per foot for the two sides facing north and south and 2$ per foot for the other two sides. Find the cost of the least expensive fence.
Answer:
Total cost will be $400
Step-by-step explanation:
Let x = be other side
y = north and south side
Area = x*y = 5000
Perimeter of the rectangle = 2x + 2y
cost of fencing = 2(1)*5000/x + 2*2x
= 10000/x + 4x
now to get the least we will take the derivative of this
C'(x) = 10000(-1/x^2) + 4 =0
x^2 = 2500
x= 50ft cost = 2*$2*50 = $200
y= 100ft cost = 2*$1*100 = $200
Total cost = $400
Answer:
First make mixed
4 x 5 = 20
20 + 2 = 22
22/5 = 4 2/5
1 x 5 = 5
5 + 1 = 6
6/5= 1 1/5
Multiply the reciprocal. The reciprocal is the fraction flipped over like 1/2 becomes 2/1
22/5 / 6/5 = 22/5 x 5/6
Multiply
22 x 5 = 110
5 x 6 = 30
110/30
Simplify
110/10=11
30/10=3
Answer is
11/3 = 3 2/3
Step-by-step explanation:
Step-by-step explanation:
Write the prime factorization of each term:
9r⁵s = 3² × r⁵ × s
6r⁴s² = 2 × 3 × r⁴ × s²
12r²s = 2² × 3 × r² × s
The greatest common factor will have all the common factors raised to their lowest exponent.
So all three terms have 3, r, and s as factors. The lowest exponent of 3 is 1. The lowest exponent of r is 2. The lowest exponent of s is 1.
GCF = 3 × r² × s
GCF = 3r²s
Factor out the GCF:
9r⁵s + 6r⁴s² − 12r²s
3r²s (3r³ + 2r²s − 4)
